Xml 在Xquery中按属性比较元素

到目前为止，我有一个名为resume的XML文档，其中包含以下方式的技能元素：

    <skills>
        <skill what = "C" level="0"></skill>
        <skill what = "Java" level="1"></skill>
        <skill what = "SQL" level="2"></skill>
        <skill what = "Lisp" level="3"></skill>
    </skills>

我需要帮助将$r1和$r2的@what和@level进行比较。我试过了

data($r1/@what) = data($r1/skills/skill/@what) along with data($r1/skills/skill/@level) = data($r2/@level)

但我似乎无法获得所需的输出。有没有办法进行这种比较？非常感谢

---

注意：我正在使用XML1.0，通过重新定义您的问题来找到他们中只有一个具备的技能，这个问题变得相当容易解决

let $skills1 :=    <skills>
        <skill what = "C" level="0"></skill>
        <skill what = "Java" level="1"></skill>
        <skill what = "SQL" level="2"></skill>
        <skill what = "Lisp" level="3"></skill>
        <skill what = "XQuery" level="4"></skill>
    </skills>
let $skills2 :=    <skills>
        <skill what = "C" level="0"></skill>
        <skill what = "Java" level="1"></skill>
        <skill what = "SQL" level="2"></skill>
        <skill what = "Lisp" level="3"></skill>
    </skills>

return
  for $skill in ($skills1, $skills2)/skill
  where not(
    $skills1/skill[deep-equal(., $skill)] and
    $skills2/skill[deep-equal(., $skill)]
  )
  return $skill

let$skills1:=
让$skills2:=
返回
对于$skill in（$skills1，$skills2）/skill
哪里没有(
$skills1/技能[深度相等（，$skill）]和
$skills2/技能[深度相等（，$skill）]
)
返回$skill

这将返回仅在技能集1中的技能（4级XQuery）。如果将整个flwor表达式包装在

return

子句中的

empty（…）

调用中，则匹配的技能集将获得

true

，如果它们有（任何）不常见的成员，则获得

false

let $skills1 :=    <skills>
        <skill what = "C" level="0"></skill>
        <skill what = "Java" level="1"></skill>
        <skill what = "SQL" level="2"></skill>
        <skill what = "Lisp" level="3"></skill>
        <skill what = "XQuery" level="4"></skill>
    </skills>
let $skills2 :=    <skills>
        <skill what = "C" level="0"></skill>
        <skill what = "Java" level="1"></skill>
        <skill what = "SQL" level="2"></skill>
        <skill what = "Lisp" level="3"></skill>
    </skills>

return
  for $skill in ($skills1, $skills2)/skill
  where not(
    $skills1/skill[deep-equal(., $skill)] and
    $skills2/skill[deep-equal(., $skill)]
  )
  return $skill