Yii2 如何通过另一个相关表（一对一关系）从相关表中获取和搜索属性

我有以下三个表格：

策略：（id，r\u可用\u taemin[fk]）--

可用_taemin:（id、名称、r_公司[fk]）--

公司：（身份证，姓名）

在策略（索引）的网格视图中，我需要显示公司名称，我已经这样做了。 但是现在我需要为公司名称添加过滤，而这里我面临着一些问题

我的搜索模式如下：

<?php

namespace app\models;

use Yii;
use yii\base\Model;
use yii\data\ActiveDataProvider;
use app\models\appmodels\AppPoliciesGeneral;

/**
 * PoliciesGeneralSearch represents the model behind the search form of `app\models\appmodels\AppPoliciesGeneral`.
 */
class PoliciesGeneralSearch extends AppPoliciesGeneral {

    public $customerName;
    public $companyName;

    /**
     * @inheritdoc
     */
    public function rules() {
        return [
            [['policy_id', 'r_deal_type', 'r_customer_id', 'r_available_taemin', 'is_active', 'r_invoice', 'isRenewed'], 'integer'],
            [['policy_type', 'policy_code', 'madmoun_name', 'payment_option', 'contract_date', 'start_date', 'end_date', 'attachment', 'sale_letters', 'paid_customer_letters', 'paid_company_letters', 'table_name', 'deactivated_at', 'created_at', 'updated_at'], 'safe'],
            [['cost', 'price', 'sale', 'tax', 'paid_customer', 'remaining_customer', 'paid_company', 'remaining_company'], 'number'],
            [['customerName', 'companyName'], 'safe'],
        ];
    }

    /**
     * @inheritdoc
     */
    public function scenarios() {
        // bypass scenarios() implementation in the parent class
        return Model::scenarios();
    }

    /**
     * Creates data provider instance with search query applied
     *
     * @param array $params
     *
     * @return ActiveDataProvider
     */
    public function search($params) {
        $query = AppPoliciesGeneral::find();

        // add conditions that should always apply here
        $dataProvider = new ActiveDataProvider([
            'query' => $query,
        ]);
        $dataProvider->setSort([
            'attributes' => [

        $query->joinWith(['rCustomer']);
        $query->joinWith(['rAvailableTaemin']);
//        $query->joinWith(['rCompany']);

                $this->load($params);

                if(!$this->validate()) {
                // uncomment the following line if you do not want to return any records when validation fails
                // $query->where('0=1');
                return $dataProvider;
                }

                // grid filtering conditions
                $query->andFilterWhere([
        'policy_id' => $this->policy_id,
                'r_deal_type' => $this->r_deal_type,
                'r_customer_id' => $this->r_customer_id,
                'r_available_taemin' => $this->r_available_taemin,
                'contract_date' => $this->contract_date,
                'start_date' => $this->start_date,
                'end_date' => $this->end_date,
                'is_active' => $this->is_active,
                'cost' => $this->cost,
                'price' => $this->price,
                'sale' => $this->sale,
                'tax' => $this->tax,
                'paid_customer' => $this->paid_customer,
                'remaining_customer' => $this->remaining_customer,
                'paid_company' => $this->paid_company,
                'remaining_company' => $this->remaining_company,
                'r_invoice' => $this->r_invoice,
                'deactivated_at' => $this->deactivated_at,
                'isRenewed' => $this->isRenewed,
                'created_at' => $this->created_at,
                'updated_at' => $this->updated_at,
                ]);

                $query->andFilterWhere([ 'like', 'policy_type', $this->policy_type])
                        ->andFilterWhere([ 'like', 'policy_code', $this->policy_code])->andFilterWhere(['like', 'madmoun_name', $this->madmoun_name])->andFilterWhere(['like', 'payment_option', $this->payment_option])->andFilterWhere(['like', 'attachment', $this->attachment])->andFilterWhere(['like', 'sale_letters', $this->sale_letters])->andFilterWhere(['like', 'paid_customer_letters', $this->paid_customer_letters])->andFilterWhere(['like', 'paid_company_letters', $this->paid_company_letters])->andFilterWhere(['like', 'table_name', $this->table_name]);

        $query->joinWith(['rCustomer' => function ($q) {
            $q->where('customers.first_name LIKE "%' . $this->customerName . '%"' .
                    'OR customers.fathers_name LIKE "%' . $this->customerName . '%"' .
                    'OR customers.last_name LIKE "%' . $this->customerName .  '%"'
            );
        }]);

//        $query->joinWith(['rAvailableTaemin' => function ($q) {
//                $q->where('companies.reprisentative_name LIKE "%' . $this->companyName . '%"');
//            }]);
//        $query->joinWith(['rCompany' => function ($q) {
                //                $q->where('companies.name LIKE "%' . $this->companyName . '%"');
//            }]);
//        $query->joinWith(['companies' => function ($q) {
//                $q->where('companies.name LIKE "%' . $this->companyName . '%"');
//            }]);

                return $dataProvider;
                }

                }

---

我不知道这里有什么问题。查看您的代码，我可以看到筛选公司名称，但它被注释掉了，为什么

总之，有几点建议：

您不必为排序设置所有属性，它是自动完成的，只是不要像这里那样覆盖它。由于您有两个虚拟属性，请执行以下操作：

$dataProvider->sort->attributes['companyName'] = [
    'asc' => ['companies.name' => SORT_ASC],
    'desc' => ['companies.name' => SORT_DESC],
    'label' => 'Company Name',
    'default' => SORT_ASC
];
$dataProvider->sort->attributes['customerName' = [
    'asc' => ['customers.first_name' => SORT_ASC, 'customers.fathers_name' => SORT_ASC, 'customers.last_name' => SORT_ASC],
    'desc' => ['customers.first_name' => SORT_DESC, 'customers.fathers_name' => SORT_DESC, 'customers.last_name' => SORT_DESC],
    'label' => Yii::t('app', 'Customer Name'),
];

就这些。其余属性将添加到自动排序中

客户筛选-已经添加了关系，您无需再次执行

if (!empty($this->customerName)) {
    $query->andWhere([
        'or',
        ['like', 'customers.first_name', $this->customerName],
        ['like', 'customers.fathers_name', $this->customerName],
        ['like', 'customers.last_name', $this->customerName],
    ]);
}

现在，公司筛选更容易，因为您只检查一列：

$query->andFilterWhere(['like', 'companies.name', $this->companyName]);

显示您的搜索模型。我面临错误：SQLSTATE[42S22]：未找到列：1054未知列“companys.name”in“where子句”谢谢您的帮助提示，我可以看到您注释掉了
$query->joinWith（['rCompany'）-这就是列未知的原因。我在公司和策略之间没有直接关系，因此我面临以下错误：SQLSTATE[42S22]：找不到列：1054未知列“policies.companyid”在“on子句”中companyid是在策略模型中计算的
$query->andFilterWhere(['like', 'companies.name', $this->companyName]);