Zend framework2 如何在加入zend framework 2中使用multiple-on子句

我正在这样做，将sql转换为zend框架sql模式

SELECT 
    jobs . *,
    c.id AS cid,
    c.name AS name,
    c.companyImage AS companyImage,
    c.logo AS logo,
    count(app.userId) AS t_app,
    app.applyStatus AS applyStatus,
    app.userId AS appUserId
FROM
    jobs
        LEFT JOIN
    companies AS c ON jobs.companyName = c.id
        LEFT JOIN
    applicants AS app ON jobs.id = app.jobId AND app.applyStatus = 1
WHERE
    jobs.ownerId = 16 AND jobs.draftId != 0 
GROUP BY jobs.id
ORDER BY jobs.id DESC
LIMIT 3 

对于这个sql，我已经为zend framework 2编写了这段代码

$adapter = $this->tableGateway->getAdapter();
        $sql     = new Sql($adapter);

        $select = $sql->select();
        $select->from('jobs')
                ->join(array('c' => 'companies'), 'jobs.companyName = c.id', array('cid' => 'id', 'name', 'companyImage', 'logo'), 'left')
                ->join(array('app' => 'applicants'), ' jobs.id = app.jobId AND app.applyStatus = 1', array('t_app'     => new Expression('count(app.userId)'), 'applyStatus', 'appUserId' => 'userId'), 'left')
                ->where("jobs.ownerId ={$userId} AND jobs.draftId != 0")
                ->group('jobs.id')
                ->order('jobs.id DESC')
                ->limit(3);

        $statement = $sql->getSqlStringForSqlObject($select);
        $results   = $adapter->query($statement, $adapter::QUERY_MODE_EXECUTE);

但不能正常工作，它会发出如下信息

SQLSTATE[42S22]: Column not found: 1054 Unknown column '1' in 'on clause'

---

问题在于这一部分：

app.applyStatus = 1

框架正在转义1，就好像它是一个列名，

1

您还需要将此部分包含在表达式中

new Expression('jobs.id = app.jobId AND app.applyStatus = 1')

---

我认为join方法的“ON”参数中表达式的使用可能取决于您使用的ZF2版本，我认为它是在2.1+中添加的，这将产生安全问题。Zf2将您的查询更改为：

Select * from tableA inner join tableB 
on `tableA`.`column` = `tableB`.`column` 
AND `tableB`.`column` = `1`

它补充道

`

---

每个部分都有安全问题！通过使用

new Expression

您将绕过它，如果您从用户条目中获得

applyStatus

，请确保对其进行过滤

基于这个答案。如果还希望转义表和列标识符，请使用以下语法：

use Zend\Db\Sql\Expression;

...

$onExpression = new Expression('? = ? AND ? = ?', 
    ['jobs.id', 'app.jobId', 'app.applyStatus', 1], 
    [Expression::TYPE_IDENTIFIER, Expression::TYPE_IDENTIFIER, 
     Expression::TYPE_IDENTIFIER, Expression::TYPE_LITERAL]
);

$select->from('jobs')
    ->join(array('app' => 'applicants'), $onExpression, array('t_app' => new Expression('count(app.userId)'), 'applyStatus', 'appUserId' => 'userId'), 'left');

表达式构造函数接受字符串，然后是参数，然后是参数类型

public function __construct($expression = '', $parameters = null, array $types = [])