Algorithm 反向链接列表-链接列表实现

这是LeetCode中的一个简单问题：反向链接列表 我有两个相似的代码，我不知道这两个代码之间有什么区别，但它输出的结果不同

第一个while循环的结果是正确的答案，但第二个有错误的答案。 而不是温度=电流。接下来，我将电流存储到temp 在while循环的最后一行，我正确地将电流切换到temp.next。 我认为他们的答案应该是一样的 但当输入{1,2,3,4,5}时，第二个解得到了错误的答案{1}

这是第二个while循环

while(current != null){
  ListNode temp = current;
  current.next = reverse;
  reverse = current;
  current = temp.next;
}

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在第二个代码段中，current=temp.next似乎将current从循环的顶部/开始或当前迭代设置为其nextvalue-毕竟，没有人给temp.next分配了什么。 但是在temp=current之后，两者都是同一事物的名称，current.next=reverse将覆盖需要但尚未保存的事物

while(current != null){
    // This line temp is keeping the reference  of current variable
    ListNode temp = current;
    // now temp and current both pointing to same value

    // This line will make the next of current variable pointing to reverse reference
    // as current and temp were same so next of temp is also pointing to the reverse
    current.next = reverse;

    // now the reverse will be changed and point to the current reference
    reverse = current;
    // so up to here reverse, temp, current all pointing to the same location
    // as all are pointing same so temp.next,curr.next and reverse.next
    // will store the previous reference 

    // current will point back to the reverse value
    // no increment is done in the whole loop
    current = temp.next;
}

while(current != null){
    // This line temp is keeping the reference  of current variable
    ListNode temp = current;
    // now temp and current both pointing to same value

    // This line will make the next of current variable pointing to reverse reference
    // as current and temp were same so next of temp is also pointing to the reverse
    current.next = reverse;

    // now the reverse will be changed and point to the current reference
    reverse = current;
    // so up to here reverse, temp, current all pointing to the same location
    // as all are pointing same so temp.next,curr.next and reverse.next
    // will store the previous reference 

    // current will point back to the reverse value
    // no increment is done in the whole loop
    current = temp.next;
}