Amazon web services AWS雅典娜-应用过滤器，然后计算百分位数

我正在使用AWS Athena计算一些指标。我有这样一个数据集：

课时数
0
10
-1
10
2.
-10
10

我试图计算这些值的百分位数，但只计算有效值的子集。有效值是

sessionnumber>1

，因此我尝试了以下方法：

with testfun AS 
    (SELECT filter(array_agg(sessionnumber), x -> x >= 1) as validvalues 
     FROM "mydate")

SELECT (percentiles(validvalues, 0.25) FROM testfun

但我得到了以下错误：

SYNTAX_ERROR: line 17:10: Unexpected parameters (array(integer), double) for function approx_percentile. Expected: approx_percentile(bigint, double) , approx_percentile(bigint, bigint, double) , approx_percentile(bigint, bigint, double, double) , approx_percentile(bigint, array(double)) , approx_percentile(bigint, bigint, array(double)) , approx_percentile(double, double) , approx_percentile(double, bigint, double, double) , approx_percentile(double, bigint, double) , approx_percentile(double, array(double)) , approx_percentile(double, bigint, array(double)) , approx_percentile(real, double) , approx_percentile(real, bigint, double, double) , approx_percentile(real, bigint, double) , approx_percentile(real, array(double)) , approx_percentile(real, bigint, array(double))

---

我理解我的错误，但我找不到一种方法来解决AWS雅典娜/普雷斯托德。即使这样做也有可能吗？

我找到了解决方法，并在这里分享：

WITH validValues AS 
(SELECT approx_percentile(sessionnumber, ARRAY[0.25,0.50,0.75,0.95, 0.99]) as percentiles from (SELECT sessionnumber from "20180407" where sessionnumber >= 1))

SELECT percentiles FROM testfun, validValues