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Android 如何编程打开关联菜单?_Android_Contextmenu - Fatal编程技术网

Android 如何编程打开关联菜单?

Android 如何编程打开关联菜单?,android,contextmenu,Android,Contextmenu,我需要在oncreate方法中打开上下文菜单。 我所做的: public class MainActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); cont = new CustomViewContainer(this); setCo

我需要在oncreate方法中打开上下文菜单。 我所做的:

public class MainActivity extends Activity
{
    @Override
    public void onCreate(Bundle savedInstanceState)
    {
        super.onCreate(savedInstanceState);
        cont = new CustomViewContainer(this);
        setContentView(cont);

        this.openContextMenu(cont);
    }
    @Override  
    public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo)
    {  
        super.onCreateContextMenu(menu, v, menuInfo);  
        menu.setHeaderTitle("Select");  
        menu.add(0, v.getId(), 0, "a");  
        menu.add(0, v.getId(), 0, "b");
        menu.add(0, v.getId(), 0, "c");  
    }
}
但是我看不到菜单。救命啊

根据,您必须首先呼叫:


我看到异常:由以下原因引起:android.view.WindowManager$BadTokenException:无法添加窗口--标记null无效;您的活动正在运行吗?哦,只需添加WindowFocusChanged,一切都很好。在哪里添加WindowFocusChanged@LeoI面临着类似的问题,但在哪里添加onWindowFocusChanged?应该向onWindowFocusChanged传递什么?对还是错@Leo@AnujKumarJha那是很久以前的事了。。也许你需要把openContextMenu(cont);进入onWindowFocusChanged方法。更多:
@Override
public void onCreate(Bundle savedInstanceState)
{
    super.onCreate(savedInstanceState);
    cont = new CustomViewContainer(this);
    setContentView(cont);

    registerForContextMenu(cont);
    openContextMenu(cont);
}