在Android（C#）中启动AlarmManager

我看到并使用了这个链接：

现在我有了这个代码：

namespace AlarmManage
{
    public class MyBroadcastReceiver : BroadcastReceiver 
    {
        public override void OnReceive(Context context, Intent intent)
        {
            Toast.MakeText(context, "Time Up... Now Vibrating !!!",
                    ToastLength.Long).Show();
            Vibrator vibrator = (Vibrator)context
                    .GetSystemService(Context.VibratorService);
            vibrator.Vibrate(2000);
        }  
    }
}

public void startAlertAtParticularTime()
{
    // alarm first vibrate at 14 hrs and 40 min and repeat itself at ONE_HOUR interval  
    intent = new Intent(this, typeof(MyBroadcastReceiver));
    pendingIntent = PendingIntent.GetBroadcast(
            this, 280192, intent, PendingIntentFlags.CancelCurrent);
    Java.Util.Calendar calendar = Java.Util.Calendar.Instance;
    calendar.TimeInMillis = Java.Lang.JavaSystem.CurrentTimeMillis();
    calendar.Set(Java.Util.CalendarField.HourOfDay, 14);
    calendar.Set(Java.Util.CalendarField.Minute, 49);
    alarmManager = (AlarmManager)GetSystemService(AlarmService);
    alarmManager.SetRepeating(AlarmType.RtcWakeup, calendar.TimeInMillis,
            AlarmManager.IntervalHour, pendingIntent);
    Toast.MakeText(this, "Alarm will vibrate at time specified", ToastLength.Long).Show();
}

我还在清单中设置了“设置警报”和“振动”

---

我的问题：我没有看到输出“Time Up…Now Vibrating！！！

我认为问题在于您没有成功声明您的

MyBroadcastReceiver

，在xamarin中，我们可以使用：

[BroadcastReceiver(Enabled = true)] 

声明此广播。就像在传统的android清单中声明它一样，如下所示：

<receiver android:name="MyBroadcastReceiver" /> 

[BroadcastReceiver(Enabled = true)]
public class MyBroadcastReceiver : BroadcastReceiver
{
    public override void OnReceive(Context context, Intent intent)
    {
        Toast.MakeText(context, "Time Up... Now Vibrating !!!",
                ToastLength.Long).Show();
        Vibrator vibrator = (Vibrator)context
                .GetSystemService(Context.VibratorService);
        vibrator.Vibrate(2000);
    }
}

现在你可以得到祝酒词了：“时间到了。。。现在振动！！！"