在Android中获取Json结果
Json问题: 我有这个格式化的JSON在Android中获取Json结果,android,json,Android,Json,Json问题: 我有这个格式化的JSON { "Table1":[ { "TableName":"LoadDistributor", "Description":"Distributor ", "MandatoryFlag":"1", "Status":"", "Priority":"0" }, { "TableName":"LoadPrice", "Description":"Price ", "M
{
"Table1":[
{
"TableName":"LoadDistributor",
"Description":"Distributor ",
"MandatoryFlag":"1",
"Status":"",
"Priority":"0"
},
{
"TableName":"LoadPrice",
"Description":"Price ",
"MandatoryFlag":"1",
"Status":"",
"Priority":"0"
},
{
"TableName":"LoadProduct",
"Description":"Product ",
"MandatoryFlag":"1",
"Status":"",
"Priority":"0"
},
{
"TableName":"RD.AlternativeProductDetail",
"Description":"AltProdutDetail",
"MandatoryFlag":"0",
"Status":"",
"Priority":"0"
},
{
"TableName":"XA.vwTown",
"Description":"Town ",
"MandatoryFlag":"1",
"Status":"",
"Priority":"0"
}
]
}
Android Json处理方法为:
public String[] getStringArrayResponseJson(SoapPrimitive node, ArrayList<String> strings) {
try{
String result = node.toString();
JSONObject json = new JSONObject(result);
// Parsing
JSONArray nameArray = json.names();
JSONArray valArray = json.toJSONArray(nameArray);
Log.i("@@@" , "===="+ valArray.length());
for (int i = 0; i < valArray.length(); i++) {
strings.add(valArray.getString(i));
}
json.put("sample key", "sample value");
Log.i("REST", "<jsonobject>\n" + json.toString()
+ "\n</jsonobject>");
}catch (JSONException e) {
e.printStackTrace();
}
公共字符串[]getStringArrayResponseJson(SoapPrimitive节点,ArrayList字符串){
试一试{
字符串结果=node.toString();
JSONObject json=新的JSONObject(结果);
//解析
JSONArray nameArray=json.names();
JSONArray valArray=json.toJSONArray(nameArray);
Log.i(“@@@@”,“=”+valArray.length());
对于(int i=0;i请告诉我json处理方法中的错误是什么:?示例代码,不确定它是否能正常工作。 我为字符串创建一个ArrayList就是为了它
ArrayList<String> list = new ArrayList<String>();
JSONArray array = jsonobject.getJSONArray("Table1");
int max = array.length();
for (int i = 0; i < max; i++) {
JSONObject tmp = array.getJSONObject(i);
list.add(tmp.getString("TableName"));
}
ArrayList list=new ArrayList();
JSONArray数组=jsonobject.getJSONArray(“表1”);
int max=array.length();
对于(int i=0;i
这可能是一种更快的方法,但只是举个例子
您可以阅读更多内容您想获取字符串数组中的所有表名字段吗?仅此字段?谢谢Pepi。是的。需要获取所有表名。根据David Olsson的回答,它现在工作正常。