Android 随意提问，不要重复

我想创建一个测验应用程序，例如我有3个问题。我想随机问他们，等所有问题都回答完后就结束比赛，但现在我没法这么做。它正在显示随机问题，但当前会重复。任何帮助都将不胜感激。提前谢谢

这是我的密码：

package com.app.twelveimams;

import android.content.DialogInterface;
import android.content.Intent;
import android.support.v7.app.AlertDialog;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
import android.widget.Toast;

import java.util.Random;

public class Quiz extends AppCompatActivity implements View.OnClickListener {

    Button btn_one, btn_two, btn_three, btn_four;
    TextView tv_question;

    private Questions question = new Questions();

    private String answer;
    private int questionLength = question.questions.length;

    Random random;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.quiz);

        random = new Random();



        btn_one = (Button)findViewById(R.id.btn_one);
        btn_one.setOnClickListener(this);
        btn_two = (Button)findViewById(R.id.btn_two);
        btn_two.setOnClickListener(this);
        btn_three = (Button)findViewById(R.id.btn_three);
        btn_three.setOnClickListener(this);
        btn_four = (Button)findViewById(R.id.btn_four);
        btn_four.setOnClickListener(this);

        tv_question = (TextView)findViewById(R.id.tv_question);

        NextQuestion(random.nextInt(questionLength));
    }

    @Override
    public void onClick(View v) {
        switch (v.getId()){
            case R.id.btn_one:
                if(btn_one.getText() == answer){
                    Toast.makeText(Quiz.this, "Correct", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }else{
                    Toast.makeText(Quiz.this, "Incorrect", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }

                break;

            case R.id.btn_two:
                if(btn_two.getText() == answer){
                    Toast.makeText(Quiz.this, "Correct", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }else{
                    Toast.makeText(Quiz.this, "Incorrect", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }

                break;

            case R.id.btn_three:
                if(btn_three.getText() == answer){
                    Toast.makeText(Quiz.this, "Correct", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }else{
                    Toast.makeText(Quiz.this, "Incorrect", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }

                break;

            case R.id.btn_four:
                if(btn_four.getText() == answer){
                    Toast.makeText(Quiz.this, "Correct", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }else{
                    Toast.makeText(Quiz.this, "Incorrect", Toast.LENGTH_SHORT).show();
                    NextQuestion(random.nextInt(questionLength));
                }

                break;
        }
    }

    private void GameOver(){
        AlertDialog.Builder alertDialogBuilder = new AlertDialog.Builder(Quiz.this);
        alertDialogBuilder
                .setMessage("Game Over")
                .setCancelable(false)
                .setPositiveButton("New Game", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        startActivity(new Intent(getApplicationContext(), MainActivity.class));
                    }
                })
                .setNegativeButton("Exit", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface dialog, int which) {
                        System.exit(0);
                    }
                });
        alertDialogBuilder.show();

    }

    private void NextQuestion(int num){
        tv_question.setText(question.getQuestion(num));
        btn_one.setText(question.getchoice1(num));
        btn_two.setText(question.getchoice2(num));
        btn_three.setText(question.getchoice3(num));
        btn_four.setText(question.getchoice4(num));

        answer = question.getCorrectAnswer(num);
    }
}

---

您可以使用

Collections.shuffle（列表）

对问题列表进行随机排序

package com.kundan.example;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;

public class Question {

    public static void main(String[] args) {

        ArrayList<String> questionList = new ArrayList<String>();
        questionList.addAll(Arrays.asList("Question 1", "Question 2", "Question 3", "Question 4", "Question 5"));
        System.out.println(questionList);
        Collections.shuffle(questionList);
        System.out.println(questionList);
    }
}

package com.kundan.example；
导入java.util.ArrayList；
导入java.util.array；
导入java.util.Collections；
公开课问题{
公共静态void main（字符串[]args）{
ArrayList questionList=新建ArrayList（）；
问题列表.addAll（数组.asList（“问题1”、“问题2”、“问题3”、“问题4”、“问题5”）；
系统输出打印LN（问题列表）；
收集。洗牌（问题列表）；
系统输出打印LN（问题列表）；
}
}

请参阅下面的链接

---

注意：字符串不会使用==进行比较，而不是使用随机生成器，存储一个乱序数字列表，然后在为该数字提问时将其删除。您可以给出一个如何进行比较的示例代码吗？将

问题设为Arraylist而不是array，您已经完成了一半。当你得到下一个问题时，把它从你的列表中删除，直到没有问题为止。请随意回答您的问题，以显示您在这方面的尝试