Android 安卓从关联菜单启动对话框

我有一个列表视图，需要长按显示我的自定义对话框。我该怎么做？我所有的尝试都没有给我带来什么。对话框从不显示，ANR发生

 @Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
    super.onCreateContextMenu(menu, v, menuInfo);
    ExpandableListView.ExpandableListContextMenuInfo info = (ExpandableListView.ExpandableListContextMenuInfo) menuInfo;
    int type = ExpandableListView.getPackedPositionType(info.packedPosition);
    int group = ExpandableListView.getPackedPositionGroup(info.packedPosition);
    int child = ExpandableListView.getPackedPositionChild(info.packedPosition);

    if (type == 1) {
        menu.add("rating");

    }
}


@Override
public boolean onContextItemSelected(MenuItem menuItem) {
    Handler handler = new Handler() {
        @Override
        public void handleMessage(Message msg) {
            int rating = msg.arg1;
            System.out.println("Rating  = " + rating);
        }
    };
    System.out.println("Create rating dialog");
    Toast.makeText(MyListActivity.this, "Ass", Toast.LENGTH_SHORT).show();
   // new RatingDialog(MyListActivity.this, handler).show();

    return super.onContextItemSelected(menuItem);

}

“分级”对话框从未显示，toast工作正常。对话前必须显示上下文菜单，或者我可以从onCreateContextMenu启动对话

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谢谢

您可能需要在对话框之前显示上下文菜单。然后您可以选择评分。

我的活动在活动组内运行。找到答案