Android Kotlin中布局的可见性

我得到了一个布局，我想使可见（这是“去”第一）点击一个按钮

<include
    android:id="@+id/registration_layout"
    layout="@layout/user_registration"
    android:visibility="gone"/>
<include
    android:id="@+id/login_layout"
    layout="@layout/login"
    android:visibility="gone"/>

---

在我的kotlin文件中，按钮的可见性有效，但布局无效。。。有什么建议吗？谢谢大家!

将布局转换为视图，而不是转换为

布局

：

fun onClickLogin(view: View) {
    val login_layout = R.id.login_layout as View //note : from import android.view.View
    val registration_layout = R.id.registration_layout as View //note: you wrote R.id.login_layout
    login_layout.visibility = View.VISIBLE
    registration_layout.visibility = View.GONE

    val btn_login = R.id.btn_login as Button
    val btn_registration = R.id.registration as Button
    btn_login.visibility = View.VISIBLE
    btn_registration = View.GONE
}

---

再次查看您的代码``val login\u layout=R.id.login\u layout as layout val registration\u layout=R.id.login\u layout as layout```注册布局val和登录布局val具有相同的参考xml…但是现在单击按钮，应用程序崩溃，我不明白为什么…@Malopieds您将布局转换为

视图

将其替换为

val loginLayout=findViewById（R.id.login\u布局）

，它成功了，谢谢！

fun onClickLogin(view: View) {
    val login_layout = R.id.login_layout as View //note : from import android.view.View
    val registration_layout = R.id.registration_layout as View //note: you wrote R.id.login_layout
    login_layout.visibility = View.VISIBLE
    registration_layout.visibility = View.GONE

    val btn_login = R.id.btn_login as Button
    val btn_registration = R.id.registration as Button
    btn_login.visibility = View.VISIBLE
    btn_registration = View.GONE
}