Android XML解析在第一个子级时停止
我正在尝试解析如下所示的XML文件:Android XML解析在第一个子级时停止,android,xml,xmlpullparser,Android,Xml,Xmlpullparser,我正在尝试解析如下所示的XML文件: <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <cartoonia xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <stagione nome="Cartoonia Speciale due per vedere se funziona"> <puntata>
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<cartoonia xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<stagione nome="Cartoonia Speciale due per vedere se funziona">
<puntata>
<numero>0</numero>
<titolo>Ciao Cipo</titolo>
<link>http://www.dimaleinpentium.com/app/download/5429764359/Cartoonia+%288%5E+Puntata%29.mp3?t=1389213968</link>
<descrizione>Ma ciao mia bella Cipo</descrizione>
</puntata>
</stagione>
<stagione nome="Stagione 1">
<puntata>
<numero>1</numero>
<titolo>Puntata 1</titolo>
<link>http://www.dimaleinpentium.com/app/download/5424302459/Cartoonia+1%5E+Puntata.mp3?t=1383736417</link>
<descrizione>Descrizione</descrizione>
</puntata>
<puntata>
<numero>2</numero>
<titolo>Puntata 2</titolo>
<link>http://www.dimaleinpentium.com/app/download/5425828359/Cartoonia+%282%5E+Puntata%29.mp3?t=1384351442</link>
<descrizione>Descrizione</descrizione>
</puntata>
<puntata>
<numero>3</numero>
<titolo>Puntata 3</titolo>
<link>http://www.dimaleinpentium.com/app/download/5427087659/Cartoonia+%283%5E+Puntata%29.mp3?t=1384981673</link>
<descrizione>Descrizione Puntata</descrizione>
</puntata>
</stagione>
<stagione nome="Cartoonia Special!">
<puntata>
<numero>0</numero>
<titolo>Ciao Cipo</titolo>
<link>http://www.dimaleinpentium.com/app/download/5429764359/Cartoonia+%288%5E+Puntata%29.mp3?t=1389213968</link>
<descrizione>Ma ciao mia bella Cipo</descrizione>
</puntata>
</stagione>
</cartoonia>
0
再见
http://www.dimaleinpentium.com/app/download/5429764359/Cartoonia+%288%5E+Puntata%29.mp3?t=1389213968
你好,我是贝拉·西波
1.
蓬塔塔1号
http://www.dimaleinpentium.com/app/download/5424302459/Cartoonia+1%5E+Puntata.mp3?t=1383736417
描述
2.
蓬塔塔2号
http://www.dimaleinpentium.com/app/download/5425828359/Cartoonia+%282%5E+Puntata%29.mp3?t=1384351442
描述
3.
蓬塔塔3
http://www.dimaleinpentium.com/app/download/5427087659/Cartoonia+%283%5E+Puntata%29.mp3?t=1384981673
潘塔塔酒店
0
再见
http://www.dimaleinpentium.com/app/download/5429764359/Cartoonia+%288%5E+Puntata%29.mp3?t=1389213968
你好,我是贝拉·西波
有了这段代码(取自AndroidDevs并进行了修改以适合我的文件),我只能先读取
,其他代码则被忽略
public Map < String, List < Entry >> parse(InputStream in ) throws XmlPullParserException, IOException {
try {
XmlPullParser parser = Xml.newPullParser();
parser.setFeature(XmlPullParser.FEATURE_PROCESS_NAMESPACES, false);
parser.setInput( in , null);
parser.nextTag();
return readFeed(parser);
} finally { in .close();
}
}
private Map < String, List < Entry >> readFeed(XmlPullParser parser) throws XmlPullParserException, IOException {
Map < String, List < Entry >> entries = new HashMap < String, List < Entry >> ();
String index = "";
parser.require(XmlPullParser.START_TAG, ns, "cartoonia");
while (parser.next() != XmlPullParser.END_TAG) {
Log.d(TAG, "> " + parser.getLineNumber() + " <");
if (parser.getEventType() != XmlPullParser.START_TAG) {
continue;
}
String name = parser.getName();
Log.d(TAG, "" + name);
if (name.equals("stagione")) {
index = parser.getAttributeValue(null, "nome");
Log.d(TAG, " " + index);
entries.put(index, new ArrayList < Entry > ());
} else if (name.equals("puntata")) {
Log.d(TAG, " Entry: " + parser.getName());
List < Entry > en = entries.get(index);
en.add(readEntry(parser));
} else {
skip(parser);
}
}
return entries;
}
// Parses the contents of an entry. If it encounters a title, summary, or link tag, hands them off
// to their respective "read" methods for processing. Otherwise, skips the tag.
private Entry readEntry(XmlPullParser parser) throws XmlPullParserException, IOException {
parser.require(XmlPullParser.START_TAG, ns, "puntata");
String title = null;
String summary = null;
String link = null;
String number = null;
while (parser.next() != XmlPullParser.END_TAG) {
if (parser.getEventType() != XmlPullParser.START_TAG) {
continue;
}
String name = parser.getName();
if (name.equals("titolo")) {
title = readTitle(parser);
} else if (name.equals("numero")) {
number = readNumber(parser);
} else if (name.equals("descrizione")) {
summary = readSummary(parser);
} else if (name.equals("link")) {
link = readLink(parser);
} else {
skip(parser);
}
}
return new Entry(title, number, summary, link);
}
publicmap>解析(InputStream-in)抛出XmlPullParserException,IOException{
试一试{
XmlPullParser=Xml.newPullParser();
setFeature(XmlPullParser.FEATURE_进程_名称空间,false);
setInput(in,null);
parser.nextTag();
返回readFeed(解析器);
}最后{in.close();
}
}
私有映射>readFeed(XmlPullParser解析器)抛出XmlPullParserException,IOException{
Map>entries=newhashmap>();
字符串索引=”;
require(XmlPullParser.START_标记,ns,“cartonia”);
while(parser.next()!=XmlPullParser.END_标记){
Log.d(TAG,“>”+parser.getLineNumber()+”实际上,我不明白这里的意思,看起来你认为“stagione”和“puntata”是邻居标记,但它们不是邻居,“puntata”是“stagione”的元素,所以,你需要在每个“stagione”中创建另一个解析器来读取“puntata”的
if(name.equals(“stagione”)){
index=parser.getAttributeValue(null,“nome”);
Log.d(标记“”+索引);
输入(索引,新数组列表());
}else if(名称等于(“puntata”)){
Log.d(标记,“条目:”+parser.getName());
Listen=entries.get(索引);
en.add(readEntry(解析器));
}
问题在于循环条件:
while (parser.next() != XmlPullParser.END_TAG) { ...
您将END\u标记
与END\u文档
混在一起。我将为您添加一个适合您的实现的示例。我添加了尽可能多的注释。请看以下内容:
int eventType;
while ((eventType = parser.getEventType()) != XmlPullParser.END_DOCUMENT) {
String current_tag = null;
switch (eventType) {
case XmlPullParser.START_DOCUMENT:
// Do the pertinent initializations here (if you need, if not, just break)
break;
case XmlPullParser.START_TAG:
current_tag = parser.getName(); // Get current tag
if (current_tag.equals("cartoonia")
continue;
else if (current_tag.equals("stagione")) // Initialize a new object to store a "stagione", probably add the name from "nome"
myStagione = new WhatEver();
else if (current_tag.equals("puntata")) // Do the proper initialization to store a "puntata"
myPuntata = new WhatEver2();
else if (myPuntata != null) { // Just do the same!
...
}
break;
case XmlPullParser.END_TAG: // This is called if you terminated processing a tag, not at the end of the XML file!
current_tag = parser.getName();
...
break;
}
eventType = parser.next(); // Next event
}
不是一个大文件。请尝试逐步使用调试器。这似乎是一个逻辑问题,而不是语法错误…在这种情况下调试有用吗?您可以打赌调试会有帮助。这是一个小文件,您可以在几分钟内完成。我的START\u标记
是“cartonia”,所以我认为END\u标记
是“cartonia”“再一次。我错了吗?在前面的步骤中,我的XML没有任何“stagione”,它只是…
,所有的“puntata”标记都被处理过。我认为你确实错了,你有几个开始标记标记,你必须区分它们(用如果句子).END\u标记
将匹配
和
,因此这是模拟过程,您需要区分它们并正确处理数据,但主要的是,您的循环条件是END\u标记
,因此您的循环在第一个上退出,而这不是您想要的,只需在END上迭代即可_文档
。我不是说你错了,但为什么“stagione”中的所有“puntata”都被处理,而只有第一个“stagione”被处理?我的意思是,如果结束标记
将同时匹配
和
,那么它应该在第一个
处停止……我需要了解这种情况,因此感谢您的帮助:)我认为这是因为当其中一个条件匹配时,您将parser
传递给您的函数,而不是parser.nextText()
,它将返回您刚才处理的下一项。我看不到这些函数的内容,但您是否通过parser.nextText()获取这些项
?顺便说一句,你不会只有2个START\u标签
和END\u标签
,而是3个,因为你的cartonia
标签也很重要。START\u文档
简单地说你正处于文档的边缘,但还没有读取任何内容,所以你也必须处理第三个标签。更多信息请点击此处
int eventType;
while ((eventType = parser.getEventType()) != XmlPullParser.END_DOCUMENT) {
String current_tag = null;
switch (eventType) {
case XmlPullParser.START_DOCUMENT:
// Do the pertinent initializations here (if you need, if not, just break)
break;
case XmlPullParser.START_TAG:
current_tag = parser.getName(); // Get current tag
if (current_tag.equals("cartoonia")
continue;
else if (current_tag.equals("stagione")) // Initialize a new object to store a "stagione", probably add the name from "nome"
myStagione = new WhatEver();
else if (current_tag.equals("puntata")) // Do the proper initialization to store a "puntata"
myPuntata = new WhatEver2();
else if (myPuntata != null) { // Just do the same!
...
}
break;
case XmlPullParser.END_TAG: // This is called if you terminated processing a tag, not at the end of the XML file!
current_tag = parser.getName();
...
break;
}
eventType = parser.next(); // Next event
}