Android 如何在Flatter中集成instagram sign_Android_Flutter_Dart_Instagram_Instagram Api

Android 如何在Flatter中集成instagram sign

android flutter dart instagram

Android 如何在Flatter中集成instagram sign,android,flutter,dart,instagram,instagram-api,Android,Flutter,Dart,Instagram,Instagram Api,我想通过instagram在我的应用程序中集成登录目前我正在使用下面的代码 Future<Token> getToken(String appId, String appSecret) async { Stream<String> onCode = await _server(); String url = "https://api.instagram.com/oauth/authorize?client_id=$appId&red

我想通过instagram在我的应用程序中集成登录

目前我正在使用下面的代码

Future<Token> getToken(String appId, String appSecret) async {
  Stream<String> onCode = await _server();
  String url =
      "https://api.instagram.com/oauth/authorize?client_id=$appId&redirect_uri=http://localhost:8585&"
      "response_type=code&scope=basic";
  final flutterWebviewPlugin = new FlutterWebviewPlugin();
  flutterWebviewPlugin.launch(url);
  final String code = await onCode.first;
  final http.Response response = await http.post(
      "https://api.instagram.com/oauth/access_token",
      body: {"client_id": appId, "redirect_uri": "http://localhost:8585", "client_secret": appSecret,
        "code": code, "grant_type": "authorization_code"});
  flutterWebviewPlugin.close();
  return new Token.fromMap(json.decode(response.body));
}

Future<Stream<String>> _server() async {
  final StreamController<String> onCode = new StreamController();
  HttpServer server =
  await HttpServer.bind(InternetAddress.loopbackIPv4, 8585);
  server.listen((HttpRequest request) async {
    final String code = request.uri.queryParameters["code"];
    request.response
      ..statusCode = 200
      ..headers.set("Content-Type", ContentType.html.mimeType)
      ..write("<html><h1>You can now close this window</h1></html>");
    await request.response.close();
    await server.close(force: true);
    onCode.add(code);
    await onCode.close();
  });
  return onCode.stream;
}

如果需要更多信息，请务必让我知道。提前谢谢。感谢您的努力。

剩余的Instagram遗留API许可（“基本许可”）已于2020年6月29日禁用。截至6月29日，第三方应用程序不再能够访问旧版API。您是否尝试过此URL:？@Goku您找到解决方案了吗？

<dict>
    <key>NSAllowsArbitraryLoads</key>
    <true/>
    <key>NSAllowsArbitraryLoadsInWebContent</key>
    <true/>
    <key>NSExceptionDomains</key>
    <dict>
        <key>localhost:8585</key>
        <dict>
            <key>NSExceptionAllowsInsecureHTTPLoads</key>
            <true/>
            <key>NSIncludesSubdomains</key>
            <true/>
        </dict>
    </dict>
</dict>