if或else if中的语句从不执行Android

我有一个基于参数返回位图对象的方法。 if条件没有执行，我不知道到底是什么问题，我正在尝试在if条件中打印Log语句，但它不起作用

public static Bitmap getWesternZodiacIcon(Context context,String westernZodiacSign)throws Exception{

      //Context context = null;

      Bitmap westernZodiacIcon = null;   

      if (westernZodiacSign.equals("Aries")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_aries);
        Log.v("westernZodiacIcon", "westernZodiacSign");
    }

      else if (westernZodiacSign.equals("Taurus")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_taurus);
          Log.v("westernZodiacIcon", westernZodiacSign);
    }

      else if (westernZodiacSign.equals("Gemini")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_gemini);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Cancer")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_cancer);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Leo")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_lion);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Virgo")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_virgin);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Libra")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_scales);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Scorpio")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_scorpion);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Sagittarius")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_sagittarius);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Capricorn")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_capricor);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Aquarius")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_aquarius);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      else if (westernZodiacSign.equals("Pisces")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_pisces);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }

      return westernZodiacIcon;
  }

你必须考虑所有的情况。添加其他内容：

...
else if (westernZodiacSign.equals("Pisces")) {
          westernZodiacIcon=BitmapFactory.decodeResource(context.getResources(),R.drawable.zodiac_pisces);
          Log.v("westernZodiacIcon", westernZodiacSign);
        }
else {
          Log.v("westernZodiacIcon", "The null hypothesis for astrology is...");                  
}

---

另外，可能会按照方法签名中的指示引发异常，因此请尝试捕获它并记录日志。

计算机不使用magic，westernZodiacSign可能不等于任何这些内容，或者您的方法从未被调用。你有没有试过放一个

Log.v（“westernZodiacSign”，westernZodiacSign）

在if测试之前？检查字符大小写，如果您不确定是否可以使用ignoreCase或先更改为小写，然后检查是否使用debugger，您可能还想用equalsIgnoreCase替换equals。是的，它可以工作，如果我将Log语句放在if条件之前，那么我可以在westernZodiacSign中获取值，但是在IF或ELSE IF中，它不起作用。因为上下文是

null

，所以代码抛出一个

NullPointerException

。您似乎忽略了调用代码中的异常。这解释了为什么日志语句无法访问。