Android 搜索sqlite记录并转到特定活动

你好，我知道这是一个基本问题，但我很困惑该怎么办。我已经硬编码了我的第一个应用程序。以下是我尝试过的：

 String Search  = SearchAuto.getText().toString();

 if(SearchAuto.getText().toString().equals("Chowchow") || 
                    SearchAuto.getText().toString().equals("Chihuahua")|| 
                    SearchAuto.getText().toString().equals("German Shephered")|| 
                    SearchAuto.getText().toString().equals("Beagle")|| 
                    SearchAuto.getText().toString().equals("Shih tzu")|| 
                    SearchAuto.getText().toString().equals("Siberian Husky")|| 
                    SearchAuto.getText().toString().equals("Pug")|| 
                    SearchAuto.getText().toString().equals("Poodle")|| 
                    SearchAuto.getText().toString().equals("Pomeranian")|| 
                    SearchAuto.getText().toString().equals("Labrador Retriever")){
                Intent myIntent = new Intent(Search.this, Dogs.class);
                myIntent.putExtra(strDog, SearchAuto.getText().toString().toLowerCase(Locale.ENGLISH));
                startActivity(myIntent);
                SearchAuto.setText("");
            }
            else if(SearchAuto.getText().toString().equals("American Shorthair") || 
                    SearchAuto.getText().toString().equals("Bengal")|| 
                    SearchAuto.getText().toString().equals("Himalayan")|| 
                    SearchAuto.getText().toString().equals("Maine Coon")|| 
                    SearchAuto.getText().toString().equals("Manx")|| 
                    SearchAuto.getText().toString().equals("Persian")|| 
                    SearchAuto.getText().toString().equals("Ragdoll")|| 
                    SearchAuto.getText().toString().equals("Russian Blue")|| 
                    SearchAuto.getText().toString().equals("Siamese")|| 
                    SearchAuto.getText().toString().equals("Sphynx")){
                Intent myIntent = new Intent(Search.this, Cats.class);
                myIntent.putExtra(strCat, SearchAuto.getText().toString().toLowerCase(Locale.ENGLISH));
                startActivity(myIntent);
                SearchAuto.setText("");
            }

但是我希望我的数据是动态的，所以我创建了一个数据库来存储我的数据

现在我的问题是如何创建查询/更改上述代码以满足我的需要

这就是我迄今为止所尝试的：

DBHelper.class

  public Cursor fetchbByAnimalType(String animalType, String breed) throws SQLException {

      Cursor mCursor = null;
      if (animalType == null  ||  animalType.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_BREED },
         null, null, null, null, null);

      }
      else {
          mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_BREED },
         KEY_ANIMALTYPE + " like '%" + animalType + "%' AND " + KEY_BREED + breed, null, null, null, null);
      }

      if (mCursor != null) {
       mCursor.moveToFirst();
      } 

      return mCursor;
}

public Cursor fetchbBreedByName(CharSequence breed) throws SQLException {

      Cursor mCursor = null;
      if (breed == null  ||  breed.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_ANIMALTYPE, KEY_DESCRIPTION, 
               KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
         null, null, null, null, null);

      }
      else {
          mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_ANIMALTYPE, KEY_DESCRIPTION, 
               KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
         KEY_BREED + " like '%" + breed + "%'", null, null, null, null);
      }

      if (mCursor != null) {
       mCursor.moveToFirst();
      } 

      return mCursor;
}

  public void onClick(View arg0) {
            String Search  = SearchAuto.getText().toString();

            Cursor cursor = dbHelper.fetchbBreedByName(Search);

            String strID, strBreed, strAnimalType;

            strID = cursor.getString(cursor.getColumnIndexOrThrow("_id"));
            strBreed = cursor.getString(cursor.getColumnIndexOrThrow("breed"));
            strAnimalType = cursor.getString(cursor.getColumnIndexOrThrow("animaltype"));

            Log.d("Search", "Search for " + strBreed + " ID is " + strID);


            if(Search.equals(strBreed) || strAnimaltype){ <<---- I don't know what condition I have to put in here!!!!!! I need help
                    Intent myIntent = new Intent(Search.this, Dogs.class);
                    myIntent.putExtra(strDog, Search);
                    startActivity(myIntent); 
            }

   }

Search.class

  public Cursor fetchbByAnimalType(String animalType, String breed) throws SQLException {

      Cursor mCursor = null;
      if (animalType == null  ||  animalType.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_BREED },
         null, null, null, null, null);

      }
      else {
          mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_BREED },
         KEY_ANIMALTYPE + " like '%" + animalType + "%' AND " + KEY_BREED + breed, null, null, null, null);
      }

      if (mCursor != null) {
       mCursor.moveToFirst();
      } 

      return mCursor;
}

public Cursor fetchbBreedByName(CharSequence breed) throws SQLException {

      Cursor mCursor = null;
      if (breed == null  ||  breed.length () == 0)  {
       mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_ANIMALTYPE, KEY_DESCRIPTION, 
               KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
         null, null, null, null, null);

      }
      else {
          mCursor = myDataBase.query(DB_TABLE, new String[] { KEY_ID, KEY_ANIMALTYPE, KEY_DESCRIPTION, 
               KEY_DIET, KEY_SHELTER, KEY_HYGIENE, KEY_MEDICATION, KEY_BREED },
         KEY_BREED + " like '%" + breed + "%'", null, null, null, null);
      }

      if (mCursor != null) {
       mCursor.moveToFirst();
      } 

      return mCursor;
}

  public void onClick(View arg0) {
            String Search  = SearchAuto.getText().toString();

            Cursor cursor = dbHelper.fetchbBreedByName(Search);

            String strID, strBreed, strAnimalType;

            strID = cursor.getString(cursor.getColumnIndexOrThrow("_id"));
            strBreed = cursor.getString(cursor.getColumnIndexOrThrow("breed"));
            strAnimalType = cursor.getString(cursor.getColumnIndexOrThrow("animaltype"));

            Log.d("Search", "Search for " + strBreed + " ID is " + strID);


            if(Search.equals(strBreed) || strAnimaltype){ <<---- I don't know what condition I have to put in here!!!!!! I need help
                    Intent myIntent = new Intent(Search.this, Dogs.class);
                    myIntent.putExtra(strDog, Search);
                    startActivity(myIntent); 
            }

   }

public void onClick（视图arg0）{
String Search=SearchAuto.getText（）.toString（）；
Cursor Cursor=dbHelper.fetchbBreedByName（搜索）；
strID strID，strBreed，strAnimalType；
strID=cursor.getString（cursor.getColumnIndexOrThrow（“_id”）；
strBreed=cursor.getString（cursor.getColumnIndexOrThrow（“品种”）；
strAnimalType=cursor.getString（cursor.getColumnIndexOrThrow（“animaltype”））；
Log.d（“搜索”，“搜索“+strBreed+”ID为“+strID”）；
如果（Search.equals（strBreed）| strAnimaltype）{假设SQLite正在工作，我想既然您已经有了
strBreed
和
strAnimaltype
，您可以这样说

if(strAnimalType.equalsIgnoreCase("cat") { /* or the value to indicate cat */
    Intent myIntent = new Intent(Search.this, Cats.class);
    myIntent.putExtra(strCat, strBreed);
    startActivity(myIntent);
} else if(strAnimalType.equalsIgnoreCase("dog") { /* or the value to indicate dog */
    Intent myIntent = new Intent(Search.this, Dogs.class);
    myIntent.putExtra(strDog, strBreed);
    startActivity(myIntent);
}

我要做的是：

创建两个ArrayList，例如DogsList和CatsList，并向其中添加相应的对象（具体来说是字符串）

希望这个东西能帮助您。
这很好，但是如果用户添加了另一条记录呢？如果代码是硬编码的，他将如何查看新创建的记录？