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Android 请支持JsonRequest_Android_Json_Android Volley - Fatal编程技术网

Android 请支持JsonRequest

Android 请支持JsonRequest,android,json,android-volley,Android,Json,Android Volley,我有以下json: { "code": "1", "status": "OK", "users": [ { "id": "5", "yazi": "launcher", "gun": "2015-08-04" }, { "id": "6", "yazi": "piano",

我有以下json:

 {
     "code": "1",
     "status": "OK",
     "users": [
         {
             "id": "5",
             "yazi": "launcher",
             "gun": "2015-08-04"
         },
         {
             "id": "6",
             "yazi": "piano",
             "gun": "2015-02-02"
         },
         {
             "id": "9",
             "yazi": "text text",
             "gun": "2015-08-05"
         },
         {
             "id": "14",
             "yazi": null
             "gun": "2015-02-02"
         }
     ] }
如果代码为1,状态为OK,我想查看用户参数。 我应该用什么?

用这个

    JSONObject obj=new JSONObject();
    String status=obj.getString("status");
    String code=obj.getString("code");
    if(code.equalsIgnoreCase("1") && status.equalsIgnoreCase("OK"))
    {
        //Parse your users array
    }

以下是解析JSONObject的代码:


检查json解析JSONObject obj=newJSONObject;字符串状态=obj.getStringstatus;字符串代码=obj.getStringcode;ifcode.equalsIgnoreCase1&&status.equalsIgnoreCaseOK{JSONArray users=object.getJSONArrayusers;forint i=0;i如何解析用户数组?
    JSONObject object = new JSONObject(jsonString);
    String code = object.optString("code");
    String status = object.optString("status");
    if (code.equals("1") && status.equals("OK")) {
        JSONArray users = object.getJSONArray("users");
        // do your code 
    }