Android 从sqlite listview按名称搜索
我已经从数据库中填充了listview。我想要的是搜索过滤器,即当用户输入字母时,搜索用户输入的所有名称。我已经浏览了很多网站,但没有找到任何解决办法。我是android开发新手,请帮助我解决这个问题。我已尝试此代码,但应用程序正在退出。我不知道代码出了什么问题Android 从sqlite listview按名称搜索,android,sqlite,listview,Android,Sqlite,Listview,我已经从数据库中填充了listview。我想要的是搜索过滤器,即当用户输入字母时,搜索用户输入的所有名称。我已经浏览了很多网站,但没有找到任何解决办法。我是android开发新手,请帮助我解决这个问题。我已尝试此代码,但应用程序正在退出。我不知道代码出了什么问题 activity_main.xml <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:tools="http:
activity_main.xml
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools" android:layout_width="match_parent"
android:layout_height="match_parent" android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
android:paddingBottom="@dimen/activity_vertical_margin" tools:context=".MainActivity">
<!-- Editext for Search -->
<EditText android:id="@+id/inputSearch"
android:layout_width="fill_parent"
android:layout_height="wrap_content"
android:hint="Search Choultry."
android:inputType="text"/>
<ListView
android:id="@+id/listViewshowall"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_centerHorizontal="true"
android:layout_below="@id/inputSearch">
</ListView>
</RelativeLayout>
MainActivity.java
package com.naman.namrathasrinivas.choultriesbangalore;
import android.app.Service;
import android.content.Context;
import android.content.DialogInterface;
import android.database.Cursor;
import android.database.SQLException;
import android.database.sqlite.SQLiteDatabase;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.text.Editable;
import android.text.TextWatcher;
import android.view.Menu;
import android.view.MenuItem;
import android.view.MotionEvent;
import android.view.View;
import android.view.WindowManager;
import android.view.inputmethod.InputMethodManager;
import android.widget.ArrayAdapter;
import android.widget.EditText;
import android.widget.ListView;
import java.io.IOException;
import java.util.ArrayList;
public class MainActivity extends AppCompatActivity {
private DatabaseHandler databaseHandler;
private SQLiteDatabase db;
private ListView listview;
EditText inputSearch;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
try {
databaseHandler = new DatabaseHandler(MainActivity.this);
databaseHandler.createdatabase();
} catch (IOException ioe) {
throw new Error("Unable to create database");
}
try {
databaseHandler.opendatabase();
} catch (SQLException sqle) {
throw sqle;
}
listview=(ListView)findViewById(R.id.listViewshowall);
// TODO Auto-generated method stub
ArrayList<StudentEntity> list=databaseHandler.Getvalue(this.toString());
ListViewAdapter adapter=new ListViewAdapter(MainActivity.this, list);
listview.setAdapter(adapter);
inputSearch = (EditText) findViewById(R.id.inputSearch);
inputSearch.addTextChangedListener(new TextWatcher() {
@Override
public void onTextChanged(CharSequence cs, int arg1, int arg2, int arg3) {
// When user changed the Text
// MainActivity.this.adapter.getFilter().filter(cs);
}
@Override
public void beforeTextChanged(CharSequence arg0, int arg1, int arg2,
int arg3) {
// TODO Auto-generated method stub
}
@Override
public void afterTextChanged(Editable arg0) {
// TODO Auto-generated method stub
ArrayList<StudentEntity> listentity = new ArrayList<StudentEntity>();
String selectQuery = "SELECT * FROM hall where name like 'b%' ";
Cursor cursor = db.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
StudentEntity sentity = new StudentEntity();
sentity.setName(cursor.getString(1));
sentity.setLocality(cursor.getString(12));
listentity.add(sentity);
} while (cursor.moveToNext());
}
// return contact list
// return listentity;
}
});
}
}
您在日志cat中遇到了什么错误?用问题贴出错误。此外,查询应该是SELECT*FROM HOLL WHERE name,如“%b%”,其中b应该替换为edittext中的文本。我没有收到任何错误。但过滤器并没有发生。你们在问题中说应用程序正在退出,所以logcat中一定有错误。。检查日志是否有错误。