Android 如何打印取代“打印”的数字&引用;
基本上,我试图通过按下任何键盘按钮来替换“?”。例如,如果问题显示为“0+1=?”,我希望用“1”替换问号 我的Java代码是:Android 如何打印取代“打印”的数字&引用;,android,Android,基本上,我试图通过按下任何键盘按钮来替换“?”。例如,如果问题显示为“0+1=?”,我希望用“1”替换问号 我的Java代码是: package org.example.question; import java.util.Random; import android.app.Activity; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widge
package org.example.question;
import java.util.Random;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
public class QuestionActivity extends Activity implements View.OnClickListener {
/** Called when the activity is first created. */
//variable for different questions
int fnum0, snum0,fnum1, snum1,fnum2, snum2,fnum3, snum3,
fnum4, snum4,fnum5, snum5,fnum6, snum6,fnum7, snum7,
fnum8, snum8,fnum9, snum9, answer;
//variable and type declaration for buttons and text
Button keyOne;
Button keyTwo;
Button keyThree;
Button keyFour;
Button keyFive;
Button keySix;
Button keySeven;
Button keyEight;
Button keyNine;
Button keyDel;
Button keyZero;
Button keyHash;
Button keySubtract;
TextView display;
TextView display1;
TextView answer0;
int question=0;
boolean q;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
//display text on screen
display1 = (TextView)findViewById(R.id.Guess);
display = (TextView)findViewById(R.id.Title);
answer0 = (TextView)findViewById(R.id.Answer);
///Code for correct and incorrect
//assigning names to each keypad
keyOne= (Button) findViewById(R.id.keypad_1);
keyTwo= (Button) findViewById(R.id.keypad_2);
keyThree= (Button) findViewById(R.id.keypad_3);
keyFour= (Button) findViewById(R.id.keypad_4);
keyFive = (Button) findViewById(R.id.keypad_5);
keySix= (Button) findViewById(R.id.keypad_6);
keySeven = (Button) findViewById(R.id.keypad_7);
keyEight = (Button) findViewById(R.id.keypad_8);
keyNine = (Button) findViewById(R.id.keypad_9);
keyZero = (Button) findViewById(R.id.keypad_0);
keySubtract = (Button) findViewById(R.id.keypad_subtract);
keyHash = (Button) findViewById(R.id.keypad_hash);
keyDel = (Button) findViewById(R.id.delete);
//setting button to produce an event when each button is pressed
keyOne.setOnClickListener(this); keyTwo.setOnClickListener(this); keyThree.setOnClickListener(this);
keyFour.setOnClickListener(this); keyFive.setOnClickListener(this); keySix.setOnClickListener(this);
keySeven.setOnClickListener(this); keyEight.setOnClickListener(this); keyNine.setOnClickListener(this);
keySubtract.setOnClickListener(this); keyHash.setOnClickListener(this); keyDel.setOnClickListener(this);
}
public void onClick(View arg0) {
switch(arg0.getId()){
case R.id.keypad_hash:
//Generates random numbers
fnum0 = (int) ((double) ((Math.random() * 10)));
snum0 = (int) ((double) ((Math.random() * 10)));
String str = "";
//genrates random number between 0 to 9
int operation = (int) ((double) ((Math.random() * 10)));
Log.d("debug", "operation value: " + operation);
if(operation == 0)
str = fnum0+ "+" + snum0+ "="+ "??";
else if(operation == 1)
str = fnum0 + "-" + snum0+ "="+ "??";
else if(operation == 2)
str = fnum0 + "*" + snum0+ "="+ "??" ;
else
str = fnum0 + "/" + snum0+ "="+ "??";
display.setText(str);
break;
case R.id.keypad_1:
if(q="?" )
{
display.setText("1");
}
else
{
return;
}
break;
case R.id.keypad_2:
display.setText("2");
break;
case R.id.keypad_3:
display.setText("3");
break;
case R.id.keypad_4:
display.setText("4");
break;
case R.id.keypad_5:
display.setText("5");
break;
case R.id.keypad_6:
display.setText("6");
break;
case R.id.keypad_7:
display.setText("7");
break;
case R.id.keypad_8:
display.setText("8");
break;
case R.id.keypad_9:
display.setText("9");
break;
case R.id.delete:
display.setText("");
break;
case R.id.keypad_0:
display.setText("0");
break;
case R.id.keypad_subtract:
display.setText("-");
break;
}
}
public void requestFocus() {
// TODO Auto-generated method stub
}
}
然而,目前它显示问题“0+1=”但当我按一时,它会删除问题并在屏幕上单独显示“1”
错误更新
case R.id.keypad_1:
public void onClick(View arg0) {
String str=null;
switch(arg0.getId()){
case R.id.keypad_hash:
//Generates random numbers
fnum0 = (int) ((double) ((Math.random() * 10)));
snum0 = (int) ((double) ((Math.random() * 10)));
//genrates random number between 0 to 9
int operation = (int) ((double) ((Math.random() * 10)));
Log.d("debug", "operation value: " + operation);
if(operation == 0)
str = fnum0+ "+" + snum0+ "="+ "??";
else if(operation == 1)
str = fnum0 + "-" + snum0+ "="+ "??";
else if(operation == 2)
str = fnum0 + "*" + snum0+ "="+ "??" ;
else
str = fnum0 + "/" + snum0+ "="+ "??";
display.setText(str);
break;
case R.id.keypad_1:
if(str.equals("??"))
{
String str1 = display.getText().toString();
display.setText(str1.replace("??", "1"));
}
else
{
return;
}
break;
应用程序正在崩溃….而不是
display.setText("1");
写
replace方法指示将str字符串上的“?”文本替换为“1”文本,因此搜索“?”文本并将其替换为该字符串上的“1”文本
要比较字符串,应使用equals方法,例如,而不是str==?
,请编写:
str.equals("?");
将键盘外壳的代码替换为此(删除if):
希望能有所帮助。我不确定所需的确切方法调用(已经有一段时间了),但您要做的是从显示中获取当前文本,修改它,然后重新显示它。我相信这会奏效:
String str = display.getText().toString();
display.setText(str.replace("??", "1"));
它给出错误“局部变量str可能尚未初始化”在onClick方法切换之前定义str变量?在“public void onClick(View arg0){”行和“switch(arg0.getId()){”行之间定义它行。我在那个确切的位置上做了,但是现在它在if语句上给了我一个不同的错误……我将添加代码,让您有一个look@sabadow初始化和声明是两个非常不同的东西,我插入了代码,应用程序现在正在崩溃…我上传了代码部分,在那里我插入了上面的代码…但是直到现在working@ahmedafzaal不要盲目复制代码。正如我所说,我不确定所需的方法调用-在TextView的API上。
getText()
返回一个CharSequence,在使用replace之前需要将其转换为字符串。@ahmedafzaal除此之外,您似乎同时应用了另一个答案的一半。它崩溃了,因为null.equals()。
case R.id.keypad_1:
String str1 = display.getText().toString();
display.setText(str1.replace("??", "1"));
break;
String str = display.getText().toString();
display.setText(str.replace("??", "1"));