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Android 如何打印取代“打印”的数字&引用;_Android - Fatal编程技术网

Android 如何打印取代“打印”的数字&引用;

Android 如何打印取代“打印”的数字&引用;,android,Android,基本上,我试图通过按下任何键盘按钮来替换“?”。例如,如果问题显示为“0+1=?”,我希望用“1”替换问号 我的Java代码是: package org.example.question; import java.util.Random; import android.app.Activity; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widge

基本上,我试图通过按下任何键盘按钮来替换“?”。例如,如果问题显示为“0+1=?”,我希望用“1”替换问号

我的Java代码是:

package org.example.question;

import java.util.Random;



import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;

public class QuestionActivity extends Activity implements View.OnClickListener {
    /** Called when the activity is first created. */

    //variable for different questions
    int fnum0, snum0,fnum1, snum1,fnum2, snum2,fnum3, snum3,
    fnum4, snum4,fnum5, snum5,fnum6, snum6,fnum7, snum7,
    fnum8, snum8,fnum9, snum9, answer;


    //variable and type declaration for buttons and text
Button keyOne;
Button keyTwo;
Button keyThree;
Button keyFour;
Button keyFive;
Button keySix;
Button keySeven;
Button keyEight;
Button keyNine;
Button keyDel;
Button keyZero;
Button keyHash;
Button keySubtract;
TextView display;
TextView display1;
TextView answer0;
int question=0;
boolean q;




    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);  

        //display text on screen

        display1 = (TextView)findViewById(R.id.Guess);
        display = (TextView)findViewById(R.id.Title);
        answer0 = (TextView)findViewById(R.id.Answer);

        ///Code for correct and incorrect

        //assigning names to each keypad
        keyOne= (Button) findViewById(R.id.keypad_1);
        keyTwo= (Button) findViewById(R.id.keypad_2);
        keyThree= (Button) findViewById(R.id.keypad_3);
        keyFour= (Button) findViewById(R.id.keypad_4);
        keyFive = (Button) findViewById(R.id.keypad_5);
        keySix= (Button) findViewById(R.id.keypad_6);
        keySeven = (Button) findViewById(R.id.keypad_7);
        keyEight = (Button) findViewById(R.id.keypad_8);
        keyNine = (Button) findViewById(R.id.keypad_9);
        keyZero = (Button) findViewById(R.id.keypad_0);
        keySubtract = (Button) findViewById(R.id.keypad_subtract);
        keyHash = (Button) findViewById(R.id.keypad_hash);
        keyDel = (Button) findViewById(R.id.delete);

        //setting button to produce an event when each button is pressed
        keyOne.setOnClickListener(this);     keyTwo.setOnClickListener(this);     keyThree.setOnClickListener(this); 
        keyFour.setOnClickListener(this);    keyFive.setOnClickListener(this);     keySix.setOnClickListener(this);     
        keySeven.setOnClickListener(this);    keyEight.setOnClickListener(this);  keyNine.setOnClickListener(this);    
        keySubtract.setOnClickListener(this);   keyHash.setOnClickListener(this);  keyDel.setOnClickListener(this);

}

    public void onClick(View arg0) {

        switch(arg0.getId()){   
        case R.id.keypad_hash:

            //Generates random numbers
            fnum0 = (int) ((double) ((Math.random() * 10))); 
            snum0 = (int) ((double) ((Math.random() * 10))); 
            String str = ""; 

            //genrates random number between 0 to 9
            int operation = (int) ((double) ((Math.random() * 10)));
            Log.d("debug", "operation value: " + operation);


            if(operation == 0)  
               str = fnum0+  "+"  +  snum0+  "="+ "??"; 

            else if(operation == 1) 
               str = fnum0 +  "-"  +  snum0+  "="+ "??"; 
            else if(operation == 2)  
               str = fnum0 +  "*"  +  snum0+  "="+ "??" ; 
            else  
               str = fnum0 +  "/"  +  snum0+  "="+ "??"; 
            display.setText(str); 
            break;

        case R.id.keypad_1:
            if(q="?" )
            {
                display.setText("1");
            }
            else
            {
                return;
            }

            break;

        case R.id.keypad_2:
            display.setText("2");
            break;

        case R.id.keypad_3:
            display.setText("3");
            break;

        case R.id.keypad_4:
            display.setText("4");
            break;

        case R.id.keypad_5:
            display.setText("5");
            break;

        case R.id.keypad_6:
            display.setText("6");
            break;

        case R.id.keypad_7:
            display.setText("7");
            break;

        case R.id.keypad_8:
            display.setText("8");
            break;

        case R.id.keypad_9:
            display.setText("9");
            break;

        case R.id.delete:
            display.setText("");
            break;

        case R.id.keypad_0:
            display.setText("0");
            break;

        case R.id.keypad_subtract:
            display.setText("-");
            break;   
        }   
     }
    public void requestFocus() {
        // TODO Auto-generated method stub

    }
}
然而,目前它显示问题“0+1=”但当我按一时,它会删除问题并在屏幕上单独显示“1”

错误更新

case R.id.keypad_1:

public void onClick(View arg0) {
            String str=null;
        switch(arg0.getId()){   
        case R.id.keypad_hash:

            //Generates random numbers
            fnum0 = (int) ((double) ((Math.random() * 10))); 
            snum0 = (int) ((double) ((Math.random() * 10))); 


            //genrates random number between 0 to 9
            int operation = (int) ((double) ((Math.random() * 10)));
            Log.d("debug", "operation value: " + operation);


            if(operation == 0)  
               str = fnum0+  "+"  +  snum0+  "="+ "??"; 

            else if(operation == 1) 
               str = fnum0 +  "-"  +  snum0+  "="+ "??"; 
            else if(operation == 2)  
               str = fnum0 +  "*"  +  snum0+  "="+ "??" ; 
            else  
               str = fnum0 +  "/"  +  snum0+  "="+ "??"; 
            display.setText(str); 
            break;

        case R.id.keypad_1:
            if(str.equals("??"))
            {
                String str1 = display.getText().toString(); 
                display.setText(str1.replace("??", "1")); 
            }
            else
            {
                return;
            }

            break;
应用程序正在崩溃….

而不是

display.setText("1");

replace方法指示将str字符串上的“?”文本替换为“1”文本,因此搜索“?”文本并将其替换为该字符串上的“1”文本

要比较字符串,应使用equals方法,例如,而不是
str==?
,请编写:

str.equals("?");
将键盘外壳的代码替换为此(删除if):


希望能有所帮助。

我不确定所需的确切方法调用(已经有一段时间了),但您要做的是从显示中获取当前文本,修改它,然后重新显示它。我相信这会奏效:

String str = display.getText().toString();
display.setText(str.replace("??", "1"));

它给出错误“局部变量str可能尚未初始化”在onClick方法切换之前定义str变量?在“public void onClick(View arg0){”行和“switch(arg0.getId()){”行之间定义它行。我在那个确切的位置上做了,但是现在它在if语句上给了我一个不同的错误……我将添加代码,让您有一个look@sabadow初始化和声明是两个非常不同的东西,我插入了代码,应用程序现在正在崩溃…我上传了代码部分,在那里我插入了上面的代码…但是直到现在working@ahmedafzaal不要盲目复制代码。正如我所说,我不确定所需的方法调用-在TextView的API上。
getText()
返回一个CharSequence,在使用replace之前需要将其转换为字符串。@ahmedafzaal除此之外,您似乎同时应用了另一个答案的一半。它崩溃了,因为
null.equals()。
case R.id.keypad_1:
      String str1 = display.getText().toString(); 
      display.setText(str1.replace("??", "1")); 
break;
String str = display.getText().toString();
display.setText(str.replace("??", "1"));