Android JsonObject检索
需要Json方面的帮助,我会混淆JsonArray和JsonObject。我想获得格式化的电话号码 这是我的密码Android JsonObject检索,android,json,jsonobjectrequest,Android,Json,Jsonobjectrequest,需要Json方面的帮助,我会混淆JsonArray和JsonObject。我想获得格式化的电话号码 这是我的密码 JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, URL, new Response.Listener<JSONObject>() { @Override
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, URL,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
JSONArray jsonArray = response.getJSONArray("result");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject result = jsonArray.getJSONObject(i);
String name = result.getString("name");
String formatted_phone_number= result.getString("formatted_phone_number");
textView.append(name + " " + " " + formatted_phone_number+ "\n");
}
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e("VOLLEY ", "ERROR");
}
});
requestQueue.add(jsonObjectRequest);
JsonObjectRequest-JsonObjectRequest=newjsonobjectrequest(Request.Method.GET,URL,
新的Response.Listener(){
@凌驾
公共void onResponse(JSONObject响应){
试一试{
JSONArray JSONArray=response.getJSONArray(“结果”);
for(int i=0;i
试试这个:
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, URL,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
JSONObject result = response.getJSONObject("result");
String name = result.getString("name");
String formatted_phone_number= result.getString("formatted_phone_number");
textView.append(name + " " + " " + formatted_phone_number+ "\n");
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e("VOLLEY ", "ERROR");
}
});
requestQueue.add(jsonObjectRequest);
JsonObjectRequest-JsonObjectRequest=newjsonobjectrequest(Request.Method.GET,URL,
新的Response.Listener(){
@凌驾
公共void onResponse(JSONObject响应){
试一试{
JSONObject结果=response.getJSONObject(“结果”);
字符串名称=result.getString(“名称”);
String formatted_phone_number=result.getString(“formatted_phone_number”);
textView.append(name+++++格式化的电话号码+“\n”);
}捕获(JSONException e){
e、 printStackTrace();
}
}
},
新的Response.ErrorListener(){
@凌驾
公共无效onErrorResponse(截击错误){
Log.e(“截击”、“错误”);
}
});
add(jsonObjectRequest);
试试这个:
JsonObjectRequest jsonObjectRequest = new JsonObjectRequest(Request.Method.GET, URL,
new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
try {
JSONObject result = response.getJSONObject("result");
String name = result.getString("name");
String formatted_phone_number= result.getString("formatted_phone_number");
textView.append(name + " " + " " + formatted_phone_number+ "\n");
} catch (JSONException e) {
e.printStackTrace();
}
}
},
new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
Log.e("VOLLEY ", "ERROR");
}
});
requestQueue.add(jsonObjectRequest);
JsonObjectRequest-JsonObjectRequest=newjsonobjectrequest(Request.Method.GET,URL,
新的Response.Listener(){
@凌驾
公共void onResponse(JSONObject响应){
试一试{
JSONObject结果=response.getJSONObject(“结果”);
字符串名称=result.getString(“名称”);
String formatted_phone_number=result.getString(“formatted_phone_number”);
textView.append(name+++++格式化的电话号码+“\n”);
}捕获(JSONException e){
e、 printStackTrace();
}
}
},
新的Response.ErrorListener(){
@凌驾
公共无效onErrorResponse(截击错误){
Log.e(“截击”、“错误”);
}
});
add(jsonObjectRequest);
结果不是arrayresult不是需要知道的arrayGlad。请接受我的回答,如果它解决了你的问题,请放弃投票,我很高兴知道。请接受我的回答,如果它解决了你的问题,请放弃投票