Android 无论我如何尝试,Firebase用户id都为空?
我制作了一个应用程序,可以让用户登录并在谷歌地图上设置标记,标记连接到一个属于设置它的用户的聊天室 现在的问题是,我无法在Chatactivity和MapFragment中获取uid,无论我如何尝试,它总是显示null,我不知道问题出在哪里 以下是三项活动: 谁能帮帮我吗~~ 后勤活动Android 无论我如何尝试,Firebase用户id都为空?,android,google-maps,firebase,firebase-realtime-database,firebase-authentication,Android,Google Maps,Firebase,Firebase Realtime Database,Firebase Authentication,我制作了一个应用程序,可以让用户登录并在谷歌地图上设置标记,标记连接到一个属于设置它的用户的聊天室 现在的问题是,我无法在Chatactivity和MapFragment中获取uid,无论我如何尝试,它总是显示null,我不知道问题出在哪里 以下是三项活动: 谁能帮帮我吗~~ 后勤活动 protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setConten
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_login);
auth = FirebaseAuth.getInstance();
if (auth.getCurrentUser() != null) {
startActivity(new Intent(LoginActivity.this, MainActivity.class));
finish();
}
//authenticate user
auth.signInWithEmailAndPassword(email, password)
.addOnCompleteListener(LoginActivity.this, new OnCompleteListener<AuthResult>() {
@Override
public void onComplete(@NonNull Task<AuthResult> task) {
// If sign in fails, display a message to the user. If sign in succeeds
// the auth state listener will be notified and logic to handle the
// signed in user can be handled in the listener.
if (!task.isSuccessful()) {
// there was an error
if (password.length() < 6) {
edUserid.setError("密碼太短,請輸入超過6個字元!");
} else {
Toast.makeText(LoginActivity.this, "登入失敗", Toast.LENGTH_LONG).show();
}
} else {
Toast.makeText(getApplicationContext(),"登入成功",Toast.LENGTH_LONG).show();
startActivity(new Intent(LoginActivity.this, MainActivity.class));
finish();
}
}
});
}
fab.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
EditText input = (EditText)findViewById(R.id.input);
// Read the input field and push a new instance
// of ChatMessage to the Firebase database
FirebaseDatabase.getInstance()
.getReference(CHAT_PATH)
.push()
.setValue(new ChatMessage(input.getText().toString(),
FirebaseAuth.getInstance()
.getCurrentUser()
.getDisplayName())
);
// Clear the input
input.setText("");
}
});
ListView listOfMessages = (ListView)findViewById(R.id.list_of_messages);
adapter = new FirebaseListAdapter<ChatMessage>(this, ChatMessage.class,
R.layout.message, FirebaseDatabase.getInstance().getReference(CHAT_PATH)) {
@Override
protected void populateView(View v, ChatMessage model, int position) {
// Get references to the views of message.xml
TextView messageText = (TextView)v.findViewById(R.id.message_text);
TextView messageUser = (TextView)v.findViewById(R.id.message_user);
TextView messageTime = (TextView)v.findViewById(R.id.message_time);
// Set their text
messageText.setText(model.getMessageText());
messageUser.setText(model.getMessageUser());
// Format the date before showing it
messageTime.setText(DateFormat.format("dd-MM-yyyy (HH:mm:ss)",
model.getMessageTime()));
}
};
listOfMessages.setAdapter(adapter);
}
}
如果有一个活动可以正确获取
uid
,如您所说,则将uid
的值保存到一个变量中,并将其存储到intent
中,并在活动之间使用。没有必要在每个活动中都获取uid。你只需要得到一次
//FirstActivity
Intent intent = new Intent(FirstActivity.this, SecondActivity.class);
intent.putExtra("uid", uid);
startActivity(intent);
要在第二个活动中恢复uid,请使用以下代码:
//SecondActivity
String uid = (String) getIntent().getExtras().get("uid");
如果您需要整个应用程序中的uid
,请使用来存储它
希望有帮助。您在任何阶段都在使用firebase身份验证吗?是的,我使用电子邮件身份验证,我有一个可以创建帐户的活动,它可以成功获取用户id,但其他活动不能。
//SecondActivity
String uid = (String) getIntent().getExtras().get("uid");