Android 如何解析结果[JSONArray]？

我正在获取JSON数据。在GridView中下载和显示图像时如何使用JSONArray。我怎样才能做到这一点？我指的是。它是JSONObject

这是我的密码

private void parseResult(String result) {
    try {
        JSONObject response = new JSONObject(result);
        JSONArray posts = response.optJSONArray("posts");
        GridItem item;
        for (int i = 0; i < posts.length(); i++) {
            JSONObject post = posts.optJSONObject(i);
            item = new GridItem();
            JSONArray img = post.getJSONArray("img");
            if (null != attachments && attachments.length() > 0) {
                JSONObject attachment = attachments.getJSONObject(0);
                if (img!= null)
                    item.setImage(img.getString("url"));
            }
            mGridData.add(item);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }
}

这是我的JSON

[
  {
    "id": "95",
    "name": "Cherry",
    "menu": [
      {
        "menu_id": "18",
        "img": "925dd3ad6d50fa5686a82af26515be5d.jpg"
      }
    ]
  },
  {...},
  {...}
]

请尝试以下代码：

有关代码，请参阅：

try{
    JSONObject  object = new JSONObject (result);
    JSONArray jsonArray = object.getJSONArray("posts");
    for(int i=0;i<jsonArray.length();i++){
         JSONObject object = jsonArray.getJSONObject(i);
         String id = object.getString("id");
         String img_url = object.getString("url");

         item = new GridItem();
          if (img_url!= null)
                   item.setImage(img_url);
            mGridData.add(item);
        }
     }
     catch (JSONException e){
           e.printStackTrace();
    }

试试看{
JSONObject对象=新的JSONObject（结果）；
JSONArray JSONArray=object.getJSONArray（“posts”）；
对于（int i=0；i，以下是您的解决方案：

    try {
        JSONObject response = new JSONObject(result);

        JSONArray menu = response.optJSONArray("menu");

        GridItem item;

        for (int i = 0; i < menu.length(); i++) {

            JSONObject post = menu.optJSONObject(i);

            String menu_id=post.getString("menu_id");

            String img=post.getString("img");


            item = new GridItem();

            item.setImage(img);


            mGridData.add(item);

        }
    } 
}

试试看{
JSONObject响应=新JSONObject（结果）；
JSONArray menu=response.optJSONArray（“菜单”）；
网格项目；
对于（int i=0；i
请使用谷歌gson库

示例JSON字符串

{
  "title": "Free Music Archive - Albums",
  "message": "",
  "errors": [],
  "total": "11259",
  "total_pages": 2252,
  "page": 1,
  "limit": "5",
  "dataset": [
    {
      "album_id": "7596",
      "album_title": "Album 1",
      "images": [
        {
          "image_id": "1",
          "user_id": null
        }
      ]
    }
  ]
}

Albums.java

class Albums {
    public String title;
    public String message;
    public List<string> errors = new ArrayList<string>();
    public String total;
    public int total_pages;
    public int page;
    public String limit;
    List<dataset> dataset = new ArrayList<dataset>();
}

哦，为什么要使用JSONArray？你没有将json字符串映射到java对象？如何解决？img.getString（“url”）我更改了image\u url，但无法解决方法getStringcheck编辑…还有两个json？你想解析哪个json图像url？org.json.JSONException:索引0超出范围[0..0）image\u url为空，我用于第二个JSON；我添加了GridItem项；在For loop.Log.i（“hello”，image\u url）；hello:925dd3ad6d50fa5686a82af26515be5d.jpg之前。但它没有显示在GridView中。我认为我在另一个代码中出错了。谢谢
{
  "title": "Free Music Archive - Albums",
  "message": "",
  "errors": [],
  "total": "11259",
  "total_pages": 2252,
  "page": 1,
  "limit": "5",
  "dataset": [
    {
      "album_id": "7596",
      "album_title": "Album 1",
      "images": [
        {
          "image_id": "1",
          "user_id": null
        }
      ]
    }
  ]
}

class Albums {
    public String title;
    public String message;
    public List<string> errors = new ArrayList<string>();
    public String total;
    public int total_pages;
    public int page;
    public String limit;
    List<dataset> dataset = new ArrayList<dataset>();
}

Albums albums = gson.fromJson(jsonString, Albums.class);