将数据发送到服务器并处理响应-Android

我正在尝试将数据发布到Web服务，但似乎无法正确执行此操作！所以我试图将json发布到服务器上，但我不知道怎么做。我需要发送此示例json以获得json响应：

内容类型：application/json HTTPMethod:POST HTTPBody: {CouponVerificationCode:594952223490，ApiKey:zfywqdyukxqpvg86snpd1osslr7q6dgegbq1f7p2yetxb56y，令牌：_2_jx1yfvtzgglntjbodw3gdzmnnagptwztwzt7dc6grnaikhx9pwv75b776gqlzou 2_SxMJjq8_2_kadmyx59hczoyaw=}

但是我得到的不是json响应，而是html响应。 有人能帮我解决这个问题吗

这是im用于与服务器通信的代码：

public static String makeRequest(String path) throws Exception {

        DefaultHttpClient httpclient = new DefaultHttpClient();
        HttpPost httpost = new HttpPost(path);
        JSONObject holder = new JSONObject();
        // holder.accumulate(name, value)


        String test = "{\"ApiKey\":\"somekey\","
                + "\"OperativeSystem\":\"0\","
                + "\"AppVersion\":\"1\","
                + "\"WebServiceVersion\":\"1\"}";
        StringEntity se = new StringEntity(test);
        Log.v("--", test);
        httpost.setEntity(se);
        httpost.setHeader("Accept", "application/json");
        httpost.setHeader("Content-type", "application/json");

        ResponseHandler responseHandler = new BasicResponseHandler();
        String response = httpclient.execute(httpost, responseHandler);
        // HttpEntity entity = response.getEntity();
        Log.v("--", response);
        return response;
    }

---

尝试使用httpGet而不是httpPost。这是我的工作代码：

            HttpClient httpclient = new DefaultHttpClient();

            // make GET request to the given URL
            HttpGet httpGet =new HttpGet(url);
            String User =  context.getString(R.string.json_uname);
            String Password =  context.getString(R.string.json_pwd);
            httpGet.setHeader("Authorization", "Basic "+ new String(Base64.encode((User +":"+ Password).getBytes(),Base64.NO_WRAP )));

            HttpResponse httpResponse = httpclient.execute(httpGet);

            // receive response as inputStream
            inputStream = httpResponse.getEntity().getContent();

            // convert inputstream to string
            if(inputStream != null)
            {
                //convertInputStreamToString(inputStream);
                BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream, "UTF-8"));
                String json = reader.readLine();
                JSONTokener tokener = new JSONTokener(json);
                 finalResult = new JSONArray(tokener);
            }
            else
                 finalResult =null;

---

您需要解析响应并将其转换为string@geekCode响应是html而不是JSON您现在得到的答案是什么？@DarkoPetkovski-您需要确认以下组合url、请求类型、请求内容类型。如果其中一个不正确，您将无法正确访问Web服务。而且也没有发布任何数据。。。