android中使用和服api的json解析
我正在解析json并从和服获取json数据。我正在从以下url获取json: 我的主要活动如下:android中使用和服api的json解析,android,json,parsing,Android,Json,Parsing,我正在解析json并从和服获取json数据。我正在从以下url获取json: 我的主要活动如下: public class MainActivity extends ListActivity { private ProgressDialog pDialog; // URL to get contacts JSON private static String url = "http://www.brankart.com/test/tra.json"; // JSON Node names p
public class MainActivity extends ListActivity {
private ProgressDialog pDialog;
// URL to get contacts JSON
private static String url = "http://www.brankart.com/test/tra.json";
// JSON Node names
private static final String lnk = "href";
private static final String d1 = "text";
private static final String dt = "property2";
// contacts JSONArray
JSONArray contacts = null;
// Hashmap for ListView
ArrayList<HashMap<String, String>> contactList;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
contactList = new ArrayList<HashMap<String, String>>();
ListView lv = getListView();
// Listview on item click listener
lv.setOnItemClickListener(new OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
// getting values from selected ListItem
String name = ((TextView) view.findViewById(R.id.name))
.getText().toString();
String cost = ((TextView) view.findViewById(R.id.email))
.getText().toString();
String description = ((TextView) view.findViewById(R.id.mobile))
.getText().toString();
// Starting single contact activity
Intent in = new Intent(getApplicationContext(),
SingleContactActivity.class);
in.putExtra(lnk, name);
in.putExtra(dt, cost);
in.putExtra(d1, description);
startActivity(in);
}
});
// Calling async task to get json
new GetContacts().execute();
}
/**
* Async task class to get json by making HTTP call
* */
private class GetContacts extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(MainActivity.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();
}
@Override
protected Void doInBackground(Void... arg0) {
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);
JSONObject nsb = jsonObj.getJSONObject("results");
// Getting JSON Array node
contacts = nsb.getJSONArray("collection1");
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);
JSONObject p1 = c.getJSONObject("property1");
String link = p1.getString(lnk);
String descp = p1.getString(d1);
String detail = p1.getString(dt);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(lnk, link);
contact.put(d1, descp);
contact.put(dt, detail);
// adding contact to contact list
contactList.add(contact);
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**
* Updating parsed JSON data into ListView
* */
ListAdapter adapter = new SimpleAdapter(
MainActivity.this, contactList,
R.layout.list_item, new String[] { d1, dt,
lnk }, new int[] { R.id.name,
R.id.email, R.id.mobile });
setListAdapter(adapter);
}
}
}
我仍然无法在listview中获取我的json。请帮助尝试如下更改背景
@Override
protected Void doInBackground(Void... arg0) {
// Creating service handler class instance
ServiceHandler sh = new ServiceHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url, ServiceHandler.GET);
Log.d("Response: ", "> " + jsonStr);
if (jsonStr != null) {
try {
JSONObject jsonObj = new JSONObject(jsonStr);
JSONObject nsb = jsonObj.getJSONObject("results");
// Getting JSON Array node
contacts = nsb.getJSONArray("collection1");
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);
JSONObject p1 = c.getJSONObject("property1");
String link = p1.getString(lnk);
String descp = p1.getString(d1);
//change here !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
String detail = c.getString(dt);
// tmp hashmap for single contact
HashMap<String, String> contact = new HashMap<String, String>();
// adding each child node to HashMap key => value
contact.put(lnk, link);
contact.put(d1, descp);
contact.put(dt, detail);
// adding contact to contact list
contactList.add(contact);
}
} catch (JSONException e) {
e.printStackTrace();
}
} else {
Log.e("ServiceHandler", "Couldn't get any data from the url");
}
return null;
}
当你尝试时会发生什么?我试图运行您的代码,但由于解析了服务器上的JSON文件,代码失败了。在问题中张贴您的stacktrace。。。