Android在方向更改后找不到片段的视图

当我的设备方向改变时，我收到一个错误。在方向改变之前，一切正常

我有一个片段（TrapCheckContainerFragment），它包含一个用于保存另一个片段（TrapCheckFragment）的框架布局。TrapCheckFragment在TrapCheckContainerFragment的onCreateView方法中创建，并使用FragmentTransaction将其放置到FrameLayout中

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {

    View rootView = inflater.inflate(R.layout.fragment_trap_check_container, container, false);

    TrapCheckFragment fragment = new TrapCheckFragment();

    ReplaceFragment(R.id.trapCheckHolder, fragment, false, feature.trapUniqueID.toString());

    return rootView;
}

private void ReplaceFragment(int idToReplace, Fragment newFragment, boolean addToBackStack, String tag){

    FragmentTransaction transaction = getFragmentManager().beginTransaction();

    transaction.replace(idToReplace, newFragment, tag);

    if(addToBackStack){
        transaction.addToBackStack(null);
    }

    transaction.commit();
}

这一切都很好，直到我旋转设备。据我所知，没有调用任何代码，但由于某种原因，FragmentManager无法找到名为trapCheckHolder的视图，该视图是用于保存子片段的FrameLayout。如果我删除了对ReplaceFragment的调用，那么当我旋转设备时，一切正常

logcat消息：

 FATAL EXCEPTION: main
 Process: com.redacted.appname, PID: 29396
 java.lang.RuntimeException: Unable to start activity ComponentInfo{com.redacted.appname/com.redacted.appname.activities.MainActivity}: java.lang.IllegalArgumentException: No view found for id 0x7f0a0042 (com.redacted.appname:id/trapCheckHolder) for fragment TrapCheckFragment{64fa6b18 #4 id=0x7f0a0042 10236}
    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2184)
    at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:2233)
    at android.app.ActivityThread.handleRelaunchActivity(ActivityThread.java:3724)
    at android.app.ActivityThread.access$900(ActivityThread.java:135)
    at android.app.ActivityThread$H.handleMessage(ActivityThread.java:1202)
    at android.os.Handler.dispatchMessage(Handler.java:102)
    at android.os.Looper.loop(Looper.java:136)
    at android.app.ActivityThread.main(ActivityThread.java:5001)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:785)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:601)
 Caused by: java.lang.IllegalArgumentException: No view found for id 0x7f0a0042 (com.redacted.appname:id/trapCheckHolder) for fragment TrapCheckFragment{64fa6b18 #4 id=0x7f0a0042 10236}
    at android.app.FragmentManagerImpl.moveToState(FragmentManager.java:882)
    at android.app.FragmentManagerImpl.moveToState(FragmentManager.java:1062)
    at android.app.BackStackRecord.run(BackStackRecord.java:684)
    at android.app.FragmentManagerImpl.execPendingActions(FragmentManager.java:1447)
    at android.app.Activity.performStart(Activity.java:5240)
    at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:2157)
    ... 10 more

我已经尝试将这个片段和父片段的setRetainInstance设置为true和false，但这没有任何区别。我在这里做的有什么明显的错误吗？有没有办法强迫创建一个新的TrapCheckFragment，而不是试图显示导致这个问题的旧的TrapCheckFragment

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如果需要，我可以提供有关任何代码或错误的更多信息。

似乎是

onCreateViewMethod

导致了问题；如果容器为null，则必须返回null：

执行类似操作以检查空值并重新创建视图：

 public View onCreateView(LayoutInflater inflater, ViewGroup container,
            Bundle savedInstanceState) {
        if (rootView == null) {
            // Inflate the layout for this fragment 
            rootView = inflater.inflate(R.layout.fragment_a, container, false);

        } else { 
            // Do not inflate the layout again. 
            // The returned View of onCreateView will be added into the fragment. 
            // However it is not allowed to be added twice even if the parent is same. 
            // So we must remove rootView from the existing parent view group 
            // (it will be added back). 
            ((ViewGroup)rootView.getParent()).removeView(rootView);
        } 
        return rootView;

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请检查，并让我知道它是否有效。

在本例中，我应该如何获取_rootView？我尝试存储创建的rootView并调用getView（），但第一个从getParent（）返回null，第二个在方向改变时返回null第一次创建片段时，其始终为null。似乎rootView.getParent（）返回null。我在调试时遇到了问题，因为如果安装了调试器并且在设备旋转后未命中任何断点，则应用程序会崩溃，而不会显示错误消息。