对话框中的Android微调器出现此错误Android.view.WindowManager$BadTokenException:无法添加窗口

我需要在我的应用程序中显示一个对话框。在此对话框中有一个微调器。因此，我使用以下代码显示对话框并填充微调器：

public class setup4 extends Activity {

public List<String> materie = new ArrayList<String>();

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.setup4);

    Database d = new Database(this);
    SQLiteDatabase db = d.getWritableDatabase();
    Cursor cursor = db.rawQuery("select * from materie", null);
    if (cursor.moveToFirst()) {
        do materie.add(cursor.getString(1)); while (cursor.moveToNext());
    }
    db.close();
}



//On bottone setup 4
public void onSetup4bottone(View v)
{
    AlertDialog.Builder customDialog = new AlertDialog.Builder(this);
    customDialog.setTitle("Aggiungi ora scolastica");
    LayoutInflater layoutInflater = (LayoutInflater)getApplicationContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View view=layoutInflater.inflate(R.layout.aggiungi_ora,null);
    customDialog.setView(view);

    Spinner spinner = (Spinner) view.findViewById(R.id.aggiungi_ora_materia);
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(view.getContext(),android.R.layout.simple_spinner_item, materie);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(new OnItemSelectedListener() {
        public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
            String selected = (String) parentView.getItemAtPosition(position);
            Toast.makeText(
                    getApplicationContext(), 
                    "hai selezionato "+selected, 
                    Toast.LENGTH_LONG
                ).show();
        }

        public void onNothingSelected(AdapterView<?> parentView) {
            // your code here
        }

    });

    customDialog.show();
}
}

微调器正确加载项目，但当我单击它更改值时，应用程序崩溃，出现以下错误：android.view.WindowManager$BadTokenException:无法添加窗口 我也发现了这个线索，但我不明白解决办法

解决 而不是 LayoutInflater LayoutInflater=LayoutInflatergetApplicationContext.getSystemServiceContext.LAYOUT\u充气机\u服务

使用

LayoutInflater LayoutInflater=getLayoutInflater

在spinner.setOnItemSelectedListener中，不要调用getApplicationContext，而是编写以下内容：

spinner.setOnItemSelectedListener(new OnItemSelectedListener() {
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        String selected = (String) parentView.getItemAtPosition(position);
        Toast.makeText(
                setup4.this,     //<===THIS LINE IS CHANGED BY ME
                "hai selezionato "+selected, 
                Toast.LENGTH_LONG
            ).show();
    }

---

尝试在不同的上下文中添加窗口

替换行ArrayAdapter=new ArrayAdapterview.getContext，android.R.layout.simple\u spinner\u项，matrie

与下面的一个：

ArrayAdapter<String> adapter = new ArrayAdapter<String>(setup4.this /**Your activity_name.this*/,android.R.layout.simple_spinner_item, materie);

---

让我知道它是否有效…

问题不在于吐司，因为它在打开的对话框中显示正确。然而，我尝试了你的解决方案，但错误仍然是一样的。谢谢你的建议：不要工作：我尝试了很多上下文，比如setup4.this，view.getContext，但它总是崩溃。我还尝试删除微调器的事件OnItemSelectedListener和onNothingSelected，但不管它如何崩溃：还有其他建议吗？