Android 在ImageView上设置适当大小的中心裁剪图像

我正在使用摄像头API拍照，我必须根据我的图像视图大小打开不同大小的摄像头。我正在关注Android sdk/sample/adroid-18中名为“ApiDemo”的示例项目。我所做的更改是在setcontentview上不设置摄像头。我已将相机设置为框架布局。起初，我的相机预览已经开始，所以我得到了相机最佳预览尺寸，并将FrameLayout参数width和height设置为wrap-content。现在相机预览比ImageView（我想要的尺寸）小。如果我将FrameLayout参数的大小设置为匹配父对象，则相机视图是拉伸的。如何解决此问题

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更新

我的相机预览尺寸很好，现在我使用的是布局上的方法，想法是我有更大的布局，然后我的ImageView，现在相机预览看起来不错。 现在我面临的问题是设置适当大小的图像，为此，我必须在像ImageView一样的视图中居中裁剪和缩放相同大小的图像。这张图像我通过拍摄方法获得并保存在SD卡中

为此，我使用以下方法：-

    public Bitmap scaleCenterCrop(Bitmap source, int newHeight, int newWidth) {
    int sourceWidth = source.getWidth();
    int sourceHeight = source.getHeight();

    // Compute the scaling factors to fit the new height and width, respectively.
    // To cover the final image, the final scaling will be the bigger 
    // of these two.
    float xScale = (float) newWidth / sourceWidth;
    float yScale = (float) newHeight / sourceHeight;
    float scale = Math.max(xScale, yScale);

    // Now get the size of the source bitmap when scaled
    float scaledWidth = scale * sourceWidth;
    float scaledHeight = scale * sourceHeight;

    // Let's find out the upper left coordinates if the scaled bitmap
    // should be centered in the new size give by the parameters
    float left = (newWidth - scaledWidth) / 2;
    float top = (newHeight - scaledHeight) / 2;

        // The target rectangle for the new, scaled version of the source bitmap will now
        // be
        RectF targetRect = new RectF(left+50, top, left + scaledWidth, top + scaledHeight+50);
//      RectF targetRect = new RectF(0, 0, newWidth, newHeight/2);
        // Finally, we create a new bitmap of the specified size and draw our new,
        // scaled bitmap onto it.
        Bitmap dest = Bitmap.createBitmap(newWidth, newHeight, source.getConfig());
        Canvas canvas = new Canvas(dest);
        canvas.drawBitmap(source, null, targetRect, null);

        return dest;
}

但结果图像质量不好。从顶部和底部切割高度角，结果图像质量不好。像素拉伸

不要告诉我使用scaleType=Center\u crop我不能在我的情况下使用它，并且不想向用户显示裁剪帧，这所有过程都不应该显示在UI上

更新

根据imageView的大小，我使用了从中心和比例裁剪图像的吹扫方法

Bitmap dstBmp = ThumbnailUtils.extractThumbnail(source, newWidth, newHeight);

但是我得到的位图与FrameLayout上显示的相机预览图不一样。因为相机预览很大。我认为这些代码裁剪了很大的区域。 我试图缩小宽度和改变高度，但没有得到我想要的相同比例的裁剪图像

在FrameLayout上自动裁剪最后一个图像帧后，我还有一个想法。我们可以从框架布局中获得设置框架吗。这怎么可能

这里有一个像这样的问题，有人能解决吗

我想通过这一行

ThumbnailUtils.extractThumbnail（source，newWidth，newHeight）来实现这一点通过这一行，我得到了图中描述的类似src的图像

这行到底要换什么

@Akanksha请使用下面的代码，您只需传递保存图像的路径，以及图像视图的高度和宽度。这个代码对我来说非常有效


    import android.graphics.Bitmap;
import android.graphics.BitmapFactory;

public class ImageHandler {
    /**
     * Decode and sample down a bitmap from a file to the requested width and
     * height.
     * 
     * @param filename
     *            The full path of the file to decode
     * @param reqWidth
     *            The requested width of the resulting bitmap
     * @param reqHeight
     *            The requested height of the resulting bitmap
     * @return A bitmap sampled down from the original with the same aspect
     *         ratio and dimensions that are equal to or greater than the
     *         requested width and height
     */


public static Bitmap decodeSampledBitmapFromFile(String filename,
            int reqWidth, int reqHeight) {

        // First decode with inJustDecodeBounds=true to check dimensions
        final BitmapFactory.Options options = new BitmapFactory.Options();
        options.inJustDecodeBounds = true;
        BitmapFactory.decodeFile(filename, options);

        // Calculate inSampleSize
        options.inSampleSize = calculateInSampleSize(options, reqWidth,
                reqHeight);

        // Decode bitmap with inSampleSize set
        options.inJustDecodeBounds = false;
        return BitmapFactory.decodeFile(filename, options);
    }



public static int calculateInSampleSize(BitmapFactory.Options options,
            int reqWidth, int reqHeight) {
        // Raw height and width of image
        final int height = options.outHeight;
        final int width = options.outWidth;
        int inSampleSize = 1;

        if (height > reqHeight || width > reqWidth) {
            if (width > height) {
                inSampleSize = Math.round((float) height / (float) reqHeight);
            } else {
                inSampleSize = Math.round((float) width / (float) reqWidth);
            }

            // This offers some additional logic in case the image has a
            // strange
            // aspect ratio. For example, a panorama may have a much larger
            // width than height. In these cases the total pixels might
            // still
            // end up being too large to fit comfortably in memory, so we
            // should
            // be more aggressive with sample down the image (=larger
            // inSampleSize).

            final float totalPixels = width * height;

            // Anything more than 2x the requested pixels we'll sample down
            // further.
            final float totalReqPixelsCap = reqWidth * reqHeight * 2;

            while (totalPixels / (inSampleSize * inSampleSize) > totalReqPixelsCap) {
                inSampleSize++;
            }
        }
        return inSampleSize;
    }
}

我在异步任务中调用此方法，因为它可能占用太多的内存和时间
我这样称呼它


class Asyncing extends AsyncTask {

        private int reqWidth;
        private int reqHeight;
        private ImageView iv;
        private String fileName;
        private ProgressDialog pd;

        public Asyncing(int reqWidth, int reqHeight, ImageView iv,
                String fileName) {
            super();
            this.reqWidth = reqWidth;
            this.reqHeight = reqHeight;
            this.fileName = fileName;
            this.iv = iv;
        }

        @Override
        protected Bitmap doInBackground(String... params) {
            return ImageHandler.decodeSampledBitmapFromFile(params[0],
                    reqWidth, reqHeight);

        }

        @Override
        protected void onPostExecute(Bitmap result) {
            iv.setImageBitmap(result);
            if (pd.isShowing()) {
                pd.setMessage(getString(R.string.completed));
                pd.dismiss();
            }

            super.onPostExecute(result);
        }

        @Override
        protected void onProgressUpdate(Void... values) {

            super.onProgressUpdate(values);
        }

        @Override
        protected void onPreExecute() {
            pd = ProgressDialog.show(CustomerDetailsActivity.this, "",
                    getString(R.string.processing_signature));
            super.onPreExecute();
        }

    }

这就是调用asynctask的方式


signedImagePath = data.getExtras().getString("imagePath");

            new Asyncing(signature_img.getWidth(), signature_img.getHeight(),
                    signature_img, "spenTest.png").execute(signedImagePath);


以上代码是根据我的要求编写的，您可以根据自己的要求进行修改
 居中裁剪图像可能有助于实现这一点

public Bitmap scaleCenterCrop(Bitmap source, int newHeight, int newWidth) {
    int sourceWidth = source.getWidth();
    int sourceHeight = source.getHeight();

    // Compute the scaling factors to fit the new height and width, respectively.
    // To cover the final image, the final scaling will be the bigger
    // of these two.
    float xScale = (float) newWidth / sourceWidth;
    float yScale = (float) newHeight / sourceHeight;
    float scale = Math.max(xScale, yScale);

    // Now get the size of the source bitmap when scaled
    float scaledWidth = scale * sourceWidth;
    float scaledHeight = scale * sourceHeight;

    // Let's find out the upper left coordinates if the scaled bitmap
    // should be centered in the new size give by the parameters
    float left = (newWidth - scaledWidth) / 2;
    float top = (newHeight - scaledHeight) / 2;

    // The target rectangle for the new, scaled version of the source bitmap will now
    // be
    RectF targetRect = new RectF(left, top, left + scaledWidth, top + scaledHeight);

    // Finally, we create a new bitmap of the specified size and draw our new,
    // scaled bitmap onto it.
    Bitmap dest = Bitmap.createBitmap(newWidth, newHeight, source.getConfig());
    Canvas canvas = new Canvas(dest);
    canvas.drawBitmap(source, null, targetRect, null);

    return dest;
}

发布你想要的图片快照！请检查更新后的简单解决方案：此处signedImagePath是图像文件的路径，spentest.png是图像文件的名称。