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Android可扩展列表:具有不同布局的组_Android_Expandablelistview - Fatal编程技术网

Android可扩展列表:具有不同布局的组

Android可扩展列表:具有不同布局的组,android,expandablelistview,Android,Expandablelistview,我想为每个组显示不同的子布局,如: @Override public View getChildView(int groupPosition, int childPosition, boolean isLastChild, View convertView, ViewGroup parent) { if (convertView == null) { switch (groupPositi

我想为每个组显示不同的子布局,如:

@Override
        public View getChildView(int groupPosition, int childPosition,
                boolean isLastChild, View convertView, ViewGroup parent) {

            if (convertView == null) {

                switch (groupPosition){

                case 0:
                    LayoutInflater inflater =  (LayoutInflater) myContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                    convertView = inflater.inflate(R.layout.child_row, null);
                    TextView tvPlayerName = (TextView) convertView.findViewById(R.id.tvPlayerName);
                    tvPlayerName.setText(arrChildelements[groupPosition][childPosition]);
                    break;

                case 1:
                    LayoutInflater inflater1 =  (LayoutInflater) myContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                    convertView = inflater1.inflate(R.layout.child_row1, null);
                    TextView tvPlayerName1 = (TextView) convertView.findViewById(R.id.tvPlayerName);
                    tvPlayerName1.setText(arrChildelements[groupPosition][childPosition]);
                    break; 

                case 2:
                    LayoutInflater inflater2 =  (LayoutInflater) myContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                    convertView = inflater2.inflate(R.layout.child_row2, null);
                    TextView tvPlayerName2 = (TextView) convertView.findViewById(R.id.tvPlayerName);
                    tvPlayerName2.setText(arrChildelements[groupPosition][childPosition]);
                    break;

                case 3:             
                    LayoutInflater inflater3 =  (LayoutInflater) myContext.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
                    convertView = inflater3.inflate(R.layout.child_row3, null);
                    TextView tvPlayerName3 = (TextView) convertView.findViewById(R.id.tvPlayerName);
                    tvPlayerName3.setText(arrChildelements[groupPosition][childPosition]);
                    break;

                }


            } return convertView;
    }
我的问题是,当单击组时,子列表在组之间进行交互更改

有人能告诉我我做错了什么吗?那是因为

if (convertView == null)
删除它,它应该可以正常工作,如果它在删除这个if语句后工作正常,则返回它,并在if(convertView==null)中添加if语句,使其显示为您想要的样子,因为删除if(convertView==null)将使滚动速度大大减慢,并使用更多的ram

例如,您可以将所有视图放在一个xml文件或一个视图中,然后在switch方法中使用setVisibility显示适合当前列表项的布局部分

if(convertView==null)

将其从子视图的自定义适配器中删除


它可以正常工作

在删除if(convertView==null)后,它可以正常工作。我不明白,我应该在if(convertView==null)中添加什么,以减少ram的使用。我必须显示7种不同的布局,很难将所有视图放在一个xml中。