Android 定期轮询后端API,在定期间隔内轮询一定次数-改装&;RxJava
我希望以预定义的定期间隔轮询后端调用一定次数。如果在循环和更新UI之间收到预期的负载,我想退出循环,否则终止轮询 下面是我在进行标准http调用时通常执行的代码Android 定期轮询后端API,在定期间隔内轮询一定次数-改装&;RxJava,android,retrofit2,rx-java2,Android,Retrofit2,Rx Java2,我希望以预定义的定期间隔轮询后端调用一定次数。如果在循环和更新UI之间收到预期的负载,我想退出循环,否则终止轮询 下面是我在进行标准http调用时通常执行的代码 //Response Model from backend API public class ApplicationStatusResponse { public boolean isActive; } //Retrofit facade @POST(v1/api/applicationStatus) Single<Appl
//Response Model from backend API
public class ApplicationStatusResponse
{
public boolean isActive;
}
//Retrofit facade
@POST(v1/api/applicationStatus)
Single<ApplicationStatusResponse> checkApplicationStatus(@Body ApplicationStatusRequest applicationRequest);
-----
DisposableSingleObserver<ApplicationStatusResponse> disposableSingleObserver = new DisposableSingleObserver<ApplicationStatusResponse>() {
@Override
public void onSuccess(ApplicationStatusResponse response) {
// Update UI Here
}
@Override
public void onError(Throwable e) {
}
};
CompositeDisposable compositeDisposable = new CompositeDisposable();
// Following call works alaways works
DisposableSingleObserver<ApplicationStatusResponse> disposable = originationRepo.checkApplicationStatus(applicationStatusRequest)
.observeOn(schedulerProvider.mainThread())
.subscribeWith(disposableSingleObserver);
compositeDisposable.add(disposable);
提前感谢您的帮助。选项#1使用filter
+take(1)
选项2使用Subject
+takeUntil
Subject<Boolean> stopSubject = PublishSubject.create();
disposable = Flowable
.interval(INITIAL_DELAY, POLLING_INTERVAL, TimeUnit.MILLISECONDS)
.takeUntil(stopSubject.asObservable())
.map(x -> originationRepo.checkApplicationStatus(applicationStatusRequest))
.take(POLL_COUNT) //YES
.subscribe(
response -> {
//update UI
boolean shouldStop = ... // calculate
if (shouldStop) {
stopSubject.onNext(true);
}
}
...
)
Subject stopSubject=PublishSubject.create();
一次性=可流动
.interval(初始延迟、轮询间隔、时间单位为毫秒)
.takeUntil(stopSubject.asObservable())
.map(x->originationRepo.checkApplicationStatus(applicationStatusRequest))
.take(POLL\u COUNT)//是
.订阅(
答复->{
//更新用户界面
布尔值shouldStop=…//计算
如果(应该停止){
stopSubject.onNext(true);
}
}
...
)
这是伪代码。我希望您能理解。(在接下来的部分中,您还可以通过抛出自定义错误/异常来“短路”可观察对象)
备选案文3:
谢谢你的回复。我不确定我的方法是否正确,但似乎代码被复制了,并且在过滤器上出现了语法错误,您不需要
DisposableSingleObserver
。在DisposableSingleObserver
中,直接放置“更新UI”代码。它将是您进行UI更新的唯一地方。在map
中放置返回true或false的函数。一般做法是,不要在流中使用外部状态。阅读地图的工作原理:以及filer
我的意思是“在doOnNext
内直接放置“更新UI”代码。”
disposable = Flowable
.interval(INITIAL_DELAY, POLLING_INTERVAL, TimeUnit.MILLISECONDS)
.map(x -> originationRepo.checkApplicationStatus(applicationStatusRequest))
.take(POLL_COUNT) //YES
.doOnNext() // update UI here
.map(response -> ) // should stop condition. true - stop, false - continue
.filter(!shouldContinue)
.take(1)
Subject<Boolean> stopSubject = PublishSubject.create();
disposable = Flowable
.interval(INITIAL_DELAY, POLLING_INTERVAL, TimeUnit.MILLISECONDS)
.takeUntil(stopSubject.asObservable())
.map(x -> originationRepo.checkApplicationStatus(applicationStatusRequest))
.take(POLL_COUNT) //YES
.subscribe(
response -> {
//update UI
boolean shouldStop = ... // calculate
if (shouldStop) {
stopSubject.onNext(true);
}
}
...
)
disposable = Flowable
.interval(INITIAL_DELAY, POLLING_INTERVAL, TimeUnit.MILLISECONDS)
.map(x -> originationRepo.checkApplicationStatus(applicationStatusRequest)) // .flatMap (?)
.take(POLL_COUNT) //YES
.doOnNext() // update UI here
.map(response -> {
if(!response.checkCondition()) {
throw new ShortCircuitException();
}
return response.data();
})
.onErrorResumeNext(throwable -> (throwable instanceof ShortCircuitException)
? Observable.empty()
: Observable.error(throwable))