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Android 如何将字符串与设备时间匹配_Android_Json - Fatal编程技术网

Android 如何将字符串与设备时间匹配

Android 如何将字符串与设备时间匹配,android,json,Android,Json,当我的设备时间介于或等于开始时间和结束时间之间时,我希望它显示ChogadiaName。这是我获取时间的方法: /*{"chogadia":[{"ChogadiaName":1,"StartTime":"5:31:19 AM","EndTime":"7:14:15 AM","Effect":"Inauspicious Chogadia"},{"ChogadiaName":3,"StartTime":"8:57:10 AM","EndTime":"10:40:5 AM","Effect":"Aus

当我的设备时间介于或等于开始时间和结束时间之间时,我希望它显示
ChogadiaName
。这是我获取时间的方法:

/*{"chogadia":[{"ChogadiaName":1,"StartTime":"5:31:19 AM","EndTime":"7:14:15 AM","Effect":"Inauspicious Chogadia"},{"ChogadiaName":3,"StartTime":"8:57:10 AM","EndTime":"10:40:5 AM","Effect":"Auspicious Chogadia"},{"ChogadiaName":4,"StartTime":"10:40:5 AM","EndTime":"12:22:59 AM","Effect":"Auspicious Chogadia"}]}*/

public class ChogadiaParser {

public static  ArrayList<Chogadia> mList=new ArrayList<Chogadia>();
public static Chogadia mChogadia;
public static String response,chogadia;
public static String Lucky="Auspicious Chogadia";
public static String UnLucky="Inauspicious Chogadia";


public static void GroupResult(String url){

    try{
      JSONArray jArray;
      JSONObject jObject;

     response=GetJsonObject.sendRequest(url);

     if(response == null){
            return;
        }

     jObject=new JSONObject(response);
     jArray=jObject.getJSONArray("chogadia");
     mList.clear();
     for(int i=0;i<jArray.length();i++){

         mChogadia=new Chogadia();
         jObject=jArray.getJSONObject(i);
         mChogadia.SetChogadiaName(jObject.getString("ChogadiaName"));
         mChogadia.SetStartTime(jObject.getString("StartTime"));
         mChogadia.SetEndTime(jObject.getString("EndTime"));
         mChogadia.SetEffect(jObject.getString("Effect"));
         mList.add(mChogadia);



         if(mathcTime(jObject.getString("StartTime"),jObject.getString("EndTime"))){


             System.out.println("Matched Name Is: " + jObject.getString("ChogadiaName"));

             break; // break loop
         }



     } 


    }catch(Exception e){
        e.printStackTrace();
    }
}



private static boolean mathcTime(String stime,String eTime) {
    SimpleDateFormat ft = new SimpleDateFormat("hh:mm:ss");

    try {
        Date ct = new Date();
        Date st = ft.parse(stime);
        Date et=ft.parse(eTime);;

        long currentTime = ((ct.getHours()*60)*60) + (ct.getMinutes()*60) + (ct.getSeconds());
        long startTime = ((st.getHours()*60)*60) + (st.getMinutes()*60) + (st.getSeconds());
        long endTime = ((et.getHours()*60)*60) + (et.getMinutes()*60) + (et.getSeconds());

        if(currentTime>=startTime || currentTime<=endTime){
            return true;
        }else{
            return false;
        }
    } catch (Exception e) {
    }
 return false;
}
}
/*{“乔加迪亚”:[{“乔加迪亚名字”:1,“开始时间”:“5:31:19 AM”,“结束时间”:“7:14:15 AM”,“效果”:“不吉利的乔加迪亚”},{“乔加迪亚名字”:3,“开始时间”:“8:57:10 AM”,“结束时间”:“10:40:5 AM”,“效果”:“吉祥的乔加迪亚”},{“乔加迪亚名字”:4,“开始时间”:“10:40:5 AM”,“结束时间”:“12:22:59 AM”,“效果”:“吉祥*/
公共类ChogadiaParser{
public static ArrayList mList=new ArrayList();
公共静态Chogadia mChogadia;
公共静态字符串响应,chogadia;
公共静态字符串Lucky=“吉祥Chogadia”;
公共静态字符串UnLucky=“unesspicous Chogadia”;
公共静态void GroupResult(字符串url){
试一试{
杰索纳雷·贾雷;
JSONObject jObject;
response=GetJsonObject.sendRequest(url);
如果(响应==null){
返回;
}
jObject=新的JSONObject(响应);
jArray=jObject.getJSONArray(“chogadia”);
mList.clear();
对于(int i=0;i=startTime | | currentTime,您应该在

或者你们可以使用哪种手表。安卓系统会发出意向信号。动作时间每分钟都会滴答作响。然后你们可以在接收器中捕捉到它,然后做你们想做的事

Broadcast Action: The current time has changed. Sent every minute. You can not receive this through components declared in manifests, only by exlicitly registering for it with Context.registerReceiver().
还有,你的代码中有什么

currentTime>=startTime || currentTime<=endTime

currentTime>=startTime | | currentTime=startTime&¤tTime如果平板电脑时间大于ServerTime(5分钟),则此代码段将返回true/false

if((serverDate.getTime()>=tabletDate.getTime()-300000)&&

(serverDate.getTime()@Scott W-你能帮我写这段代码吗…-我的prblm是如何在应用程序打开时匹配时间并显示Chogadia名称…-我有这两个条件,但没有给出确切的输出否,
currentTime>=startTime | | currentTime=startTime&¤tTimeMath很有用。只需画一个数字轴,将startTime和endTime放在其中,并使用你的不等式区域,你可以清楚地看到一切。-代码正在工作,但现在是新的prblm。我遇到过它只匹配下午时间或从下午12点开始。它与上午9点到11点的时间不匹配AM@Kalai.G-如何检查上午|下午在这是上午还是下午。您需要检查平板电脑时间还是服务器时间?
currentTime>=startTime || currentTime<=endTime
currentTime>=startTime && currentTime<=endTime
    if ((serverDate.getTime() >= tabletDate.getTime() - 300000) &&
    (serverDate.getTime() <= tabletDate.getTime() + 300000)) 
        {
         isTrue = true;
            } else { 
                    isTrue = false;
                }