android:json异常

我从服务器端得到一些响应，我需要解析这些响应，但不是通过名称，也就是说，响应会不断变化

  type = "data_updates";
        updates =             {
            "offers_all" =                 {
                columns =                     (
                    "record_id",
                    "display_name",
                    "sorting_name",
                    latitude,
                    longitude,
                    "custom_ad_banner_resource_id",
                    description,
                    "website_url",
                    "phone_number",
                    hours,
                    advertiser,
                    "street_address",
                    "offer_id",
                    "offer_section",
                    "start_date",
                    "end_date",
                    "custom_leaf_template",
                    "location_area"
                );
                data =                     (
                                            (
                        "09834-234234",
                        "The Example Offer",
                        "example offer, the",
                        "-122.234234",
                        "31.2342343",
                        "",
                        "An Example of an Offer.",
                        "http=>//freeruntech.com/",
                        "1.707.555.1212",
                        "10am - 5pm",
                        Yes,
                        "3145 State Street,\nCalistoga, CA, 94500",
                        "",
                        "",
                        "2011-08-24",
                        "2011-12-31",
                        "",
                        Napa
                    )}

我使用以下代码获取主要JSONObject

if (show.get("type").equals("data_updates")) 
{   
    JSONObject data_updates = show.getJSONObject("updates");

    JSONArray array_containing_values= new JSONArray();
    JSONArray data_updates_values=data_updates.names();

    System.out.println(data_updates_values);
    for(int m=0; m<data_updates_values.length(); m++)
    {
        JSONObject obj = new JSONObject((String) data_updates_values.get(m));
        JSONArray names = new JSONArray();
        names= obj.toJSONArray(names);                  
        System.out.println(names);
    }
}

如何获取数据和列的值

JSonobjects

有人能帮我吗

---

谢谢你是这样做的吗

HttpEntity entity = response.getEntity();

            if (entity != null) {
                // Read the content stream
                InputStream instream = entity.getContent();
                Header contentEncoding = response.getFirstHeader("Content-Encoding");
                if (contentEncoding != null && contentEncoding.getValue().equalsIgnoreCase("gzip")) {
                    instream = new GZIPInputStream(instream);
                }

                // convert content stream to a String
                String resultString= convertStreamToString(instream);
                Log.v(null, "resultString "+resultString);
                instream.close();


                // Transform the String into a JSONObject
                if(resultString!=null){
                    jsonObjRecv = new JSONObject(resultString);

                }

            // Raw DEBUG output of our received JSON object:
            Log.i(TAG,"<jsonobject>\n"+jsonObjRecv.toString()+"\n</jsonobject>");

---

问题在于它不是一个有效的json。在json=中，被替换为：，并且值数组以[开头，以]结尾，没有；在json中。请看以下链接

---

它看起来不像是有效的JSON。你确定你得到了JSON的响应吗？@Nikita事实上我刚刚在这里写了一部分，实际上响应非常大。也许你可以用它来验证你的响应，只是为了确定。JSON的符号中没有括号“（）”，你是如何得到你的响应的？

HttpEntity entity = response.getEntity();

            if (entity != null) {
                // Read the content stream
                InputStream instream = entity.getContent();
                Header contentEncoding = response.getFirstHeader("Content-Encoding");
                if (contentEncoding != null && contentEncoding.getValue().equalsIgnoreCase("gzip")) {
                    instream = new GZIPInputStream(instream);
                }

                // convert content stream to a String
                String resultString= convertStreamToString(instream);
                Log.v(null, "resultString "+resultString);
                instream.close();


                // Transform the String into a JSONObject
                if(resultString!=null){
                    jsonObjRecv = new JSONObject(resultString);

                }

            // Raw DEBUG output of our received JSON object:
            Log.i(TAG,"<jsonobject>\n"+jsonObjRecv.toString()+"\n</jsonobject>");

JSONObject jsshow = new JSONObject(show)