Angularjs 如何在angular UI网格中设置columnDefs属性中的过滤器
我在应用程序中有一个角度ui网格,如果任何字段值为null或空,我希望隐藏一个字段 $scope.gridOptions = { paginationPageSize: 10, columnDefs: [ { displayName: 'First Name', field: 'firstName', headerCellClass: "GridHeader" }, { displayName: 'Last Name', field: 'lastName', headerCellClass: "GridHeader" }, { displayName: 'Active Status', field: 'activeStatus', headerCellClass: "GridHeader" }, { displayName: 'RoleName', field: 'roleName', headerCellClass: "GridHeader" }, ] }; $scope.gridOptions={ 分页页面大小:10, columnDefs:[ {displayName:'firstName',field:'firstName',headerCellClass:“GridHeader”}, {displayName:'Last Name',field:'lastName',headerCellClass:'GridHeader'}, {displayName:'activeStatus',field:'activeStatus',headerCellClass:'GridHeader}, {displayName:'RoleName',字段:'RoleName',headerCellClass:'GridHeader}, ] }; 如何在现场安装过滤器。假设上述代码中我的角色名为空/空,则从网格中隐藏角色字段 非常感谢您的帮助和建议。提前谢谢:)是的,我修好了Angularjs 如何在angular UI网格中设置columnDefs属性中的过滤器,angularjs,angular-ui-grid,Angularjs,Angular Ui Grid,我在应用程序中有一个角度ui网格,如果任何字段值为null或空,我希望隐藏一个字段 $scope.gridOptions = { paginationPageSize: 10, columnDefs: [ { displayName: 'First Name', field: 'firstName', headerCellClass: "GridHeader" }, { displayName: 'Last Name', f
var result = [];
var gridValue= [
{ displayName: 'First Name', field: 'firstName', headerCellClass: "GridHeader" },
{ displayName: 'Last Name', field: 'lastName', headerCellClass: "GridHeader" },
{ displayName: 'Active Status', field: 'activeStatus', headerCellClass: "GridHeader" },
{ displayName: 'RoleName', field: 'roleName', headerCellClass: "GridHeader" },
];
在响应中,我检查了空值
if(response.data != null)
{
if (response.data.roleName === null) {
result = gridValue.slice(0, 3);
}
else {
result = gridValue;
}
$scope.gridOptions = {
paginationPageSize: 10,
columnDefs: result,
};
}
这对我有帮助:)是的,我修好了
var result = [];
var gridValue= [
{ displayName: 'First Name', field: 'firstName', headerCellClass: "GridHeader" },
{ displayName: 'Last Name', field: 'lastName', headerCellClass: "GridHeader" },
{ displayName: 'Active Status', field: 'activeStatus', headerCellClass: "GridHeader" },
{ displayName: 'RoleName', field: 'roleName', headerCellClass: "GridHeader" },
];
在响应中,我检查了空值
if(response.data != null)
{
if (response.data.roleName === null) {
result = gridValue.slice(0, 3);
}
else {
result = gridValue;
}
$scope.gridOptions = {
paginationPageSize: 10,
columnDefs: result,
};
}
这对我有帮助:)我建议只使用
that.grid.columnDefs[3].visible = false;
我还没有测试过,但它应该比从定义中删除列并将定义重新应用到网格更有效
我认为还可以将可见性设置为检查数据的函数
that.grid.columnDefs[3].visible = function () {
// replace with code checking grid.data
return false;
}
我建议只使用
that.grid.columnDefs[3].visible = false;
我还没有测试过,但它应该比从定义中删除列并将定义重新应用到网格更有效
我认为还可以将可见性设置为检查数据的函数
that.grid.columnDefs[3].visible = function () {
// replace with code checking grid.data
return false;
}
无法找到解决方案。请建议。谢天谢地,我找不到解决办法。请建议。谢谢