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Angularjs delete函数的API不再工作,不再';不能从数组中删除任何内容?_Angularjs_Node.js_Api_Mongoose - Fatal编程技术网

Angularjs delete函数的API不再工作,不再';不能从数组中删除任何内容?

Angularjs delete函数的API不再工作,不再';不能从数组中删除任何内容?,angularjs,node.js,api,mongoose,Angularjs,Node.js,Api,Mongoose,当我试图从视图中删除一个帖子时,显然表明它已被删除。然而,当我返回到提供者路径时,我可以通过下面的路径找到所有先前的数组成员。但是,当我在发送/发布的路线中时,不会显示以前删除的成员。有趣的是,刷新页面后,它不再显示视图中的记录。 在下面的路径中,在我从命令提示符尝试时,post将消失: /providers/553b72c9f6d0020425d37f37/posts router.get('/providers/:provider/posts', function(req, res) {

当我试图从视图中删除一个帖子时,显然表明它已被删除。然而,当我返回到提供者路径时,我可以通过下面的路径找到所有先前的数组成员。但是,当我在发送/发布的路线中时,不会显示以前删除的成员。有趣的是,刷新页面后,它不再显示视图中的记录。 在下面的路径中,在我从命令提示符尝试时,post将消失:

/providers/553b72c9f6d0020425d37f37/posts

router.get('/providers/:provider/posts', function(req, res) {  Provider.findById(req.params.provider).select('posts').populate('posts').exec(function(err, provider) {
        if(err){ return next(err); }
        res.json(provider.posts);
    });
});
然而,在这个路径中,我可以找到包含9个成员的posts数组。似乎任何被移除的都不起作用

router.get('/providers', function(req, res, next) {
    Provider.find(function(err, providers){
        if(err){ return next(err); }

        res.json(providers);
    });
});
以下是我在服务器端的删除功能:

router.delete('/providers/:provider/posts/:post',auth, function(req, res){
    console.log("I ma running from server")
    return Post.findById(req.params.post, function(err, post){
        return post.remove(function(err){
            if(!err){
                Post.update({_id: post.provider}, {$pull : {posts : post._id}}, function(err, numberAffected){
                    console.log(numberAffected);
                    if(!err){
                        return console.log('removed post id');
                    } else {
                        return console.log(err);
                    }
                });
                console.log('post removed');
                return res.send('');
            } else{
                console.log(err);
            }
        });
    });
});
这里是我在工厂里的客户端:

 ob.deletePost = function (provider_id,post_id) {
        return $http.delete(urlBase +'/providers/' + provider_id +'/posts/' + post_id ,
            {
            headers: {Authorization: 'Bearer '+auth.getToken()}
        });
    };
在控制器中:

$scope.deletePost= function (provider_id,post_id) {
        //console.log('PROVIDER',provider_id);
        // console.log('POST',post_id);
        // console.log('COMMENT',comment_id);

        providers.deletePost(provider_id,post_id)

            .success(function () {
                $scope.status = 'Deleted Post! Refreshing post list.';

                for (var i = 0; i < $scope.provider.posts.length; i++) {
                    var post = $scope.provider.posts[i];
                    // console.log(i,comment,comment_id)
                    //console.log(comment.ID);
                    if (post._id === post_id) {
                        //console.log(provider._id === provider_id)
                        // console.log(provider._id);
                        $scope.provider.posts.splice(i, 1);
                        //providers.getAllComments();
                        break;
                    }
                }
                // $scope.providers = null; // i am not sure how to write  for comment as well?

            })
            .error(function (error) {
                $scope.status = 'Unable to delete comment: ' + error.message;
            });
    };
$scope.deletePost=函数(提供程序id,post id){
//console.log('PROVIDER',PROVIDER\u id);
//console.log('POST',POST\u id);
//console.log('COMMENT',COMMENT\u id);
providers.deletePost(provider\u id,post\u id)
.success(函数(){
$scope.status='已删除帖子!正在刷新帖子列表';
对于(变量i=0;i<$scope.provider.posts.length;i++){
var post=$scope.provider.posts[i];
//日志(i,comment,comment\u id)
//console.log(comment.ID);
if(post.\u id==post\u id){
//console.log(provider.\u id===provider\u id)
//console.log(provider.\u id);
$scope.provider.posts.拼接(i,1);
//providers.getAllComments();
打破
}
}
//$scope.providers=null;//我也不知道如何编写注释?
})
.错误(函数(错误){
$scope.status='无法删除注释:'+错误消息;
});
};
以下是我观点的一部分:

<div ng-repeat="provider in providers"> <!-- | orderBy:'-upvotes'-->
        <span class="glyphicon glyphicon-thumbs-up"
              ng-click="incrementUpvotes(provider)"></span>
        <span style="font-size:18px; margin-left:10px;">
                {{provider.upvotes}} - <strong>{{provider.name}}</strong>
          <span ng-if="provider.posts.length !== 0">
                <a ui-sref="post({provider_id : provider._id})">{{provider.posts.length}} Posts </a>
              <button class="btn btn-xs btn-info pull-right"  ng-click="modalUpdateProvider('size',provider)">Edit</button>
          </span>

{{provider.upvoces}-{{provider.name}}
.

谢谢。

我相信您在更新声明中使用了错误的型号:

router.delete('/providers/:provider/posts/:post', auth, function(req, res) {
  console.log("I ma running from server");
  // NOTE: you could also include a where clause to ensure the 
  // provider ID matches as well. This would prevent someone from using any
  // provider ID (inclduing one that doesn't exist) with a post ID.
  return Post.findById(req.params.post, function(err, post) {
    // Might want to check for an error here
    console.log('post removed');

    return post.remove(function(err) {
      if (!err) {
        //Post.update({
        Provider.update({
          _id: post.provider // or req.params.provider
        }, {
          $pull: {
            posts: post._id
          }
        }, function(err, numberAffected) {
          console.log(numberAffected);
          if (!err) {
            console.log('removed post id');
          } else {
            console.log(err);
          }
          return res.send('');
        });
      } else {
        console.log(err);
      }
    });
  });
});
此外,您还可以使用findByIdAndXXX方法以及内置承诺将这些方法链接在一起,以便于阅读:

router.delete('/providers/:provider/posts/:post', auth, function(req, res) {
  console.log("I ma running from server");
  // NOTE: you could also include a where clause to ensure the 
  // provider ID matches as well. This would prevent someone from using any
  // provider ID (inclduing one that doesn't exist) with a post ID.
  return Post.findByIdAndRemove(req.params.post).exec().then(function(post) {
    console.log('post removed');
    return Provider.findByIdAndUpdate(req.params.provider, {
        $pull: {
          posts: post._id
        }
      }, {
        new: true
      } // Return updated document
    ).exec(); // return promise to be evaluated for next handler
  }).then(function(provider) {
    console.log('removed post id');
    res.send('');
  }).then(null, function(err) {
    console.log(err);
    //might want to send a response error here
  });
});
更新:要使用where子句,您需要切换到findOneAndXXX方法:

router.delete('/providers/:provider/posts/:post', auth, function(req, res) {
  console.log("I am running from server");
  return Post.findOneAndRemove({_id: req.params.post, provider_id: req.params.provider}).exec().then(function(post) {
    console.log('post removed');
    return Provider.findByIdAndUpdate(req.params.provider, {
        $pull: {
          posts: post._id // or req.params.post
        }
      }, {
        new: true
      } // Return updated document
    ).exec(); // return promise to be evaluated for next handler
  }).then(function(provider) {
    console.log('removed post id');
    res.send('');
  }).then(null, function(err) {
    console.log(err);
    //might want to send a response error here
  });
});

您可以删除服务器端的a post,但不更新客户端的提供程序。您必须重新加载提供程序或手动删除帖子。@michael,我更新了新的。我在控制器里面做的,你太棒了。。多谢各位@Jason更新了答案以显示如何在查询中执行。那么,您是指仅使用findOneAndRemove的from where子句?因为我看不出和前一个有多大区别。我想你是指条件语句。Mongoose在内部将条件对象转换为mongoDB的where子句。