ansible：如何检查shell输出

我是Ansible（1.9.2）的新手。我想检查当前的zlib版本。如果不是1.2.8，则Ansible需要从源代码处安装

检查当前zlib版本的命令为

root@node2 zlib-1.2.8]# cat /usr/local/include/zlib.h | grep "#define ZLIB_VERSION" | awk '{print $3}'
"1.2.8

我的易解码

 - name: "Check zlib version "
      shell: "cat /usr/local/include/zlib.h | grep \"#define ZLIB_VERSION\" | awk '{print $3}'"
      register: zlib_version
    - name: "Debug result"
      debug: result
    - name: "Build zlib "
      command: "{{ item }} chdir=/home/zlib-1.2.8"
      with_items:
        - "./configure --prefix=/usr/local --shared"
        - make
        - make install
      when: "zlib_version!=1.2.8"

调试打印“hello world”

如何检查shell输出并相应地运行命令

我已更改调试：var=zlib\u version.stdout。它打印

TASK: [Debug result] ********************************************************** 
ok: [192.168.111.81] => {
    "var": {
        "zlib_version.stdout": "\"1.2.8\""
    }
}

但是，现在我需要编写

zlib\u version.stdout.find（“\'1.2.8\”）==-1

，两次。有没有一种简单的方法可以让Ansible在匹配

zlib\u version.stdout.find（“\”1.2.8\”）==-1时跳过所有命令、shell和unarchive

 - name: "Check zlib version "
      shell: "cat /usr/local/include/zlib.h | grep \"#define ZLIB_VERSION\" | awk '{print $3}'"
      ignore_errors: true
      register: zlib_version
    - unarchive: src=/home/files/nigex/zlib-1.2.8.tar.gz   dest=/home/
      when: zlib_version.stdout.find ("\"1.2.8\"") == -1

    - name: "Debug result"
      debug: var=zlib_version.stdout
    - name: "Build zlib "
      command: "{{ item }} chdir=/home/zlib-1.2.8"
      with_items:
        - "./configure --prefix=/usr/local --shared"
        - make
        - make install
      when: zlib_version.stdout.find ("\"1.2.8\"") == -1

shell命令的输出可通过
stdout
property获得。因此，
zlib\u version.stdout
将为您提供命令的输出

- name: "Debug result"
  debug: var=zlib_version.stdout

可以创建一个简单的脚本来避免两次写入条件。大概是这样的：

# file roles/zlib/tasks/main.yml
---
- unarchive: src=/home/files/nigex/zlib-1.2.8.tar.gz   dest=/home/

- name: "Build zlib "
  command: "{{ item }} chdir=/home/zlib-1.2.8"
  with_items:
    - "./configure --prefix=/usr/local --shared"
    - make
    - make install

然后仅当条件为true时才包含角色

# pre_tasks is needed instead of tasks since this needs to be run before the role is included

pre_tasks:
  - name: "Check zlib version "
    shell: "cat /usr/local/include/zlib.h | grep \"#define ZLIB_VERSION\" | awk '{print $3}'"
    ignore_errors: true
    register: zlib_version

roles:
  - { role: zlib, when: "zlib_version.stdout.find ('\"1.2.8\"') == -1" }

谢谢你的回复。我已经更改了调试行，它可以正常工作。但是，我无法比较shell输出。@Khoga，我认为您的做法正好相反。您需要
zlib\u version.stdout.find（“\'1.2.8\”）==-1
。谢谢。它是有效的：）。有一件事，请查看我的帖子。现在我需要输入两次[when:zlib\u version.stdout.find（“\”1.2.8\”）=-1]。有没有一个简单的方法，使Ansible跳过所有的命令，无存档和shell等，当它是真的吗？谢谢朋友。你真的帮了大忙。谢谢：）
# pre_tasks is needed instead of tasks since this needs to be run before the role is included

pre_tasks:
  - name: "Check zlib version "
    shell: "cat /usr/local/include/zlib.h | grep \"#define ZLIB_VERSION\" | awk '{print $3}'"
    ignore_errors: true
    register: zlib_version

roles:
  - { role: zlib, when: "zlib_version.stdout.find ('\"1.2.8\"') == -1" }