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Apache spark 如何获取集群信息以调用RESTAPI(从驱动程序中)?_Apache Spark_Yarn_Emr_Amazon Cloudwatch - Fatal编程技术网

Apache spark 如何获取集群信息以调用RESTAPI(从驱动程序中)?

Apache spark 如何获取集群信息以调用RESTAPI(从驱动程序中)?,apache-spark,yarn,emr,amazon-cloudwatch,Apache Spark,Yarn,Emr,Amazon Cloudwatch,我想使用Spark REST API获取指标并发布到cloud watch。但RESR API类似于: val url = "http://<host>:4040/api/v1/applications/<app-name>/stages" 我得到: java.io.IOException: Server returned HTTP response code: 500 for URL: http://112.21.2.151:4040/api/v1/applicat

我想使用Spark REST API获取指标并发布到cloud watch。但RESR API类似于:

 val url = "http://<host>:4040/api/v1/applications/<app-name>/stages"
我得到:

java.io.IOException: Server returned HTTP response code: 500 for URL: http://112.21.2.151:4040/api/v1/applications/application_1515337161733_0001
  at sun.net.www.protocol.http.HttpURLConnection.getInputStream0(HttpURLConnection.java:1876)
  at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1474)
  at java.net.URL.openStream(URL.java:1045)
  at scala.io.Source$.fromURL(Source.scala:141)
  at scala.io.Source$.fromURL(Source.scala:131)
  ... 64 elided

如果您知道主机,则可以查询
应用程序
端点:

http://localhost:4040/api/v1/applications
并解析结果以获得应用程序id

要从应用程序中获取
applicationId
host
,请使用相应的
SparkContext
方法:

val spark: SparkSession

spark.sparkContext.applicationId
spark.sparkContext.uiWebUrl
val spark: SparkSession

spark.sparkContext.applicationId
spark.sparkContext.uiWebUrl