Arrays 如何在python中删除数组中的重复项

我试图实现一个差分函数，它从一个列表中减去另一个列表并返回结果。以下是我到目前为止的情况：

def array_diff(a, b):
    for e in b[:]:
        for i in a:
            a.remove(i)
    return a


in1 = [1, 2, 2]
in2 = [1]
print(array_diff(in1, in2))

我有两个样本测试，我想运行

Test.assert_equals(array_diff([1,2,2], [1]), [2,2], "a was [1,2,2], b was [1], expected [2,2]")
Test.assert_equals(array_diff([1,2,2], [2]), [1], "a was [1,2,2], b was [2], expected [1]")

---

如何能够多次删除相同的值？

这是否回答了您的问题？

array_diff = lambda a, b: [ i for i in a if i not in b]

array_diff(in1,[1])
 [2, 2]

array_diff(in1,[2])
 [1]