Arrays jq—在JSON对象中找到数组的名称，然后获取数组的内容

我有以下JSON数组

[
    {
        "city": "Seattle",
        "array10": [
            "1",
            "2"
        ]
    },
    {
        "city": "Seattle",
        "array11": [
            "3"
        ]
    },
    {
        "city": "Chicago",
        "array20": [
            "1",
            "2"
        ]
    },
    {
        "city": "Denver",
        "array30": [
            "3"
        ]
    },
    {
        "city": "Reno",
        "array50": [
            "1"
        ]
    }
]

我的任务如下：对于每个已知的

“city”

值，获取数组的名称，对于每个数组，获取打印/显示的内容。城市和数组的名称是唯一的，数组的内容是不唯一的

结果应如下所示：

Now working on Seattle
Seattle has the following arrays: 
array10
array11
Content of the array10
1
2
Content of the array11
3

Now working on Chicago
Chicago has the following arrays: 
array20
Content of the array array20
1
2

Now working on Denver
Denver has the following arrays: 
array30
Content of the array array30
3

Now working on Reno
Denver has the following arrays: 
array50
Content of the array array50
1

现在，对于每个城市名称（已提供/已知），我可以使用以下过滤器查找阵列名称（我可以将城市名称放入变量中）：

然后将这些名称分配给一个bash变量，并在新的循环中迭代以获取每个数组的内容

虽然我可以用上面的方法得到我想要的，但我的问题是——有没有更有效的方法用jq来做到这一点

第二个相关问题——如果我的JSON具有以下结构，从速度/效率/简单性的角度来看，它会使我的任务更容易吗

[
    {
        "name": "Seattle",
        "content": {
            "array10": [
                "1",
                "2"
            ],
            "array11": [
                "3"
            ]
        }
    },
    {
        "name": "Chicago",
        "content": {
            "array20": [
                "1",
                "2"
            ]
        }
    },
    {
        "name": "Denver",
        "content": {
            "array30": [
                "3"
            ]
        }
    },
    {
        "name": "Reno",
        "content": {
            "array50": [
                "1"
            ]
        }
    }
]

---

使用-r命令行选项，以下程序生成如下所示的输出：

group_by(.city)[]
| .[0].city as $city
| map(keys_unsorted[] | select(test("^array"))) as $arrays
| "Now working on \($city)",
  "\($city) has the following arrays:",
  $arrays[],
  (.[] | to_entries[] | select(.key | test("^array"))
   | "Content of the \(.key)", .value[])

输出

---

您将决定使用哪种JSON格式的第一版还是第二版？答案应该基于哪个版本？@Inian，最有效/最简单的版本，但我不知道，这就是为什么我问这两个问题。我已经有了自己的第1个版本的解决方案，但是如果第2个版本的JSON解决方案更简单/更容易，那么我需要首先将第1个版本转换为第2个版本，并对其应用过滤器/解决方案。

group_by(.city)[]
| .[0].city as $city
| map(keys_unsorted[] | select(test("^array"))) as $arrays
| "Now working on \($city)",
  "\($city) has the following arrays:",
  $arrays[],
  (.[] | to_entries[] | select(.key | test("^array"))
   | "Content of the \(.key)", .value[])

Now working on Chicago
Chicago has the following arrays:
array20
Content of the array20
1
2
Now working on Denver
Denver has the following arrays:
array30
Content of the array30
3
Now working on Reno
Reno has the following arrays:
array50
Content of the array50
1
Now working on Seattle
Seattle has the following arrays:
array10
array11
Content of the array10
1
2
Content of the array11
3