Arrays MPI广播二维阵列

我打算用MPI学习并行编程。我有一些错误

#include "mpi.h"
#include <stdio.h>
#include <stdlib.h>


int main(int argc, char** argv)
{
    int procNum, procRank;
    int m,n;
    int sumProc = 0, sumAll = 0;
    int** arr;
    MPI_Status status;

    MPI_Init ( &argc, &argv );

    MPI_Comm_size ( MPI_COMM_WORLD, &procNum ); 
    MPI_Comm_rank ( MPI_COMM_WORLD, &procRank );

    if (procRank == 0)
    {   
        printf("Type the array size \n");
        scanf("%i %i", &m, &n); 
    }
    MPI_Bcast(&m, 1, MPI_INT, 0, MPI_COMM_WORLD);
    MPI_Bcast(&n, 1, MPI_INT, 0, MPI_COMM_WORLD);

    arr = new int*[m];
    for (int i = 0; i < m; i++)
        arr[i] = new int[n];

    if (procRank == 0)
    {
        for (int i = 0; i < m; i++)
        {
            for (int j = 0; j < n; j++)
            {
                    arr[i][j] = rand() % 30;
                    printf("%i ", arr[i][j]);
            }
            printf("\n");
        }
    }

    MPI_Bcast(&arr[0][0], m*n, MPI_INT, 0, MPI_COMM_WORLD);

    for (int i = procRank; i < n; i += procNum)
        for (int j = 0; j < m; j++)
            sumProc += arr[j][i];

    MPI_Reduce(&sumProc,&sumAll,1,MPI_INT,MPI_SUM,0,MPI_COMM_WORLD);

    if (procRank == 0)
    {
        printf("sumAll = %i", sumAll);
    }

    delete *arr;

    MPI_Finalize();
    return 0;
}

这是什么问题？也许问题出在MPI_Bcast中

我补充道

for (int i = 0; i < m; i++)
    MPI_Bcast(arr[i], n, MPI_INT, 0, MPI_COMM_WORLD);

它在这里解决了我的问题

arr = new int*[m];
for (int i = 0; i < m; i++)
    arr[i] = new int[n];

---

假设所有数组在内存中都是连续的。因为它们不是，所以会得到不同的值。

在我看来，在不成功的版本中，您（错误地）假设数组在内存中是连续的。如何避免这种情况？或者在std:：vector或int**中使用MPI是不可能的，我只能使用int[m][n]之类的东西？

MPI_Bcast(&arr[0][0], m*n, MPI_INT, 0, MPI_COMM_WORLD);

arr = new int*[m];
for (int i = 0; i < m; i++)
    arr[i] = new int[n];

MPI_Bcast(&arr[0][0], m*n, MPI_INT, 0, MPI_COMM_WORLD);