Arrays Swift-合并两个数组，同时删除重复的键并将数组值添加到一起

我有两个数组，看起来像下面的例子。我想做的是将两者合并在一起。如果它们的键相等，则删除重复项并将两个值相加

非常感谢您的帮助，非常感谢

当前代码：

struct Example: Codable {
    var key: String
    var value: Int
}

var first: [Example] = []
var second: [Example] = []

first.append(Example(key: "1", value: 10))
first.append(Example(key: "2", value: 10))
first.append(Example(key: "3", value: 10))

second.append(Example(key: "2", value: 10))
second.append(Example(key: "3", value: 10))
second.append(Example(key: "4", value: 10))


let merged = Array(Dictionary([first, second].joined().map { ($0.key, $0)}, uniquingKeysWith: { $1 }).values)

Example(key: "3", value: 20)
Example(key: "1", value: 10)
Example(key: "2", value: 20)
Example(key: "4", value: 10)

当前打印

Example(key: "3", value: 10)
Example(key: "1", value: 10)
Example(key: "2", value: 10)
Example(key: "4", value: 10)

我想做什么：

struct Example: Codable {
    var key: String
    var value: Int
}

var first: [Example] = []
var second: [Example] = []

first.append(Example(key: "1", value: 10))
first.append(Example(key: "2", value: 10))
first.append(Example(key: "3", value: 10))

second.append(Example(key: "2", value: 10))
second.append(Example(key: "3", value: 10))
second.append(Example(key: "4", value: 10))


let merged = Array(Dictionary([first, second].joined().map { ($0.key, $0)}, uniquingKeysWith: { $1 }).values)

Example(key: "3", value: 20)
Example(key: "1", value: 10)
Example(key: "2", value: 20)
Example(key: "4", value: 10)

你快到了

在

uniqueKeysWith

参数中，您应该创建一个新的

示例

，该示例包含相同的键以及两个参数值的总和：

let merged = Array(Dictionary([first, second].joined().map { ($0.key, $0)}, uniquingKeysWith: { Example(key: $0.key, value: $0.value + $1.value) }).values)

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很好用！非常感谢你！！