Arrays 使用python中的字典列表合并2个不同的数组

我正在尝试合并2个数组，如下所示：

第一:

[650001.88, 300442.2,   18.73,  0.575,  650002.094, 300441.668, 18.775]
[650001.96, 300443.4,   18.7,   0.65,   650002.571, 300443.182, 18.745]
[650002.95, 300442.54,  18.82,  0.473,  650003.056, 300442.085, 18.745]
[650005.28, 300444.76,  18.93,  0.463,  650005.368, 300444.395, 18.659]
[650006.17, 312903.26,  14.68,  0.442,  650006.146, 312902.819, 14.68]
[650006.18, 312902.89,  14.91,  0.243,  650006.146, 312902.819, 14.68]
[650006.17, 300445.16,  18.75,  0.402,  650006.286, 300444.792, 18.635]
[650006.8,  312904.65,  14.54,  0.479,  650006.904, 312905.096, 14.68]
[650006.78, 312905.06,  14.81,  0.184,  650006.904, 312905.096, 14.68]
[650011.84, 300447.74,  18.56,  0.546,  650011.836, 300447.197, 18.507]
[650012.96, 300446.92,  18.71,  0.553,  650013.238, 300446.497, 18.488]
[650014.07, 300447.51,  18.41,  0.614,  650014.2,   300446.914, 18.473]
[650001.18, 312862.23,  8.79,   40.338, 650014.526, 312899.965, 13.797]
[650001.19, 312861.88,  9.15,   40.619, 650014.526, 312899.965, 13.797]

证券交易委员会：

第一个数组的第七列与第二个数组的第一列共享相同的参数。我的第一个数组包含近5000万条记录，第二个数组包含50000条记录。我正在尝试基于共享列合并两个数组

我的最终数组应该是这样的

715316  650001.88   300442.2    18.73   0.575   650002.094  300441.668  18.775  1
715317  650001.96   300443.4    18.7    0.65    650002.571  300443.182  18.745  2
715310  650002.95   300442.54   18.82   0.473   650003.056  300442.085  18.745  3
715304  650005.28   300444.76   18.93   0.463   650005.368  300444.395  18.659  4
129733  650006.17   312903.26   14.68   0.442   650006.146  312902.819  14.68   5
129739  650006.18   312902.89   14.91   0.243   650006.146  312902.819  14.68   5
715303  650006.17   300445.16   18.75   0.402   650006.286  300444.792  18.635  6
129851  650006.8    312904.65   14.54   0.479   650006.904  312905.096  14.68   7
129852  650006.78   312905.06   14.81   0.184   650006.904  312905.096  14.68   7
715302  650011.84   300447.74   18.56   0.546   650011.836  300447.197  18.507  8
715301  650012.96   300446.92   18.71   0.553   650013.238  300446.497  18.488  9
715250  650014.07   300447.51   18.41   0.614   650014.2    300446.914  18.473  10
129121  650001.18   312862.23   8.79    40.338  650014.526  312899.965  13.797  11
129127  650001.19   312861.88   9.15    40.619  650014.526  312899.965  13.797  11
129128  650001.19   312861.54   9.53    40.897  650014.526  312899.965  13.797  11

我设法做到了这一点，但现在唯一的问题是我的d1字典覆盖了重复的键，结果输出不正确

def merge_arrays(first, sec):

    d1 = dict((x[5], x[0:]) for x in first)
    d2 = dict((x[0], x[1:]) for x in sec)

    finaldict = {key:(d2[key], d1[key]) for key in d2}

    arr2 = []

    for x in finaldict.values():
        arr2.append(x)
        #print(x)

    arr = np.asarray(arr2)  
    a = np.array(arr)
    output = np.array(list(map(np.concatenate,a)))

我想我需要使用字典列表，而不仅仅是普通字典。但我不知道如何将数组转换为具有重复键的字典列表

编辑：

我尝试使用@zipa方法：

d2 = dict((x[0], x[1:]) for x in sec)
finaldict = [item + d2[item[5]] for item in first]


print(finaldict[0])


[650001.88, 300442.2,   18.73,  0.575,  650002.094, 300441.668, 18.775]

我猜，我的字典之所以没有增值，是因为它的创建方式。当我选中d2[项目[4]]时，它创建了我[1]，而不仅仅是1。我之所以访问项[4]，是因为在我的数据中，它与示例中的项[5]具有相同的值

当我访问时，它会创建这个

---

但仍然无法为我的合并阵列增加价值。

理解可以做到：

first = [[650001.88, 300442.2,   18.73,  0.575,  650002.094, 300441.668, 18.775],
         [650001.96, 300443.4,   18.7,   0.65,   650002.571, 300443.182, 18.745],
         [650002.95, 300442.54,  18.82,  0.473,  650003.056, 300442.085, 18.745],
         [650005.28, 300444.76,  18.93,  0.463,  650005.368, 300444.395, 18.659],
         [650006.17, 312903.26,  14.68,  0.442,  650006.146, 312902.819, 14.68],
         [650006.18, 312902.89,  14.91,  0.243,  650006.146, 312902.819, 14.68],
         [650006.17, 300445.16,  18.75,  0.402,  650006.286, 300444.792, 18.635],
         [650006.8,  312904.65,  14.54,  0.479,  650006.904, 312905.096, 14.68],
         [650006.78, 312905.06,  14.81,  0.184,  650006.904, 312905.096, 14.68],
         [650011.84, 300447.74,  18.56,  0.546,  650011.836, 300447.197, 18.507],
         [650012.96, 300446.92,  18.71,  0.553,  650013.238, 300446.497, 18.488],
         [650014.07, 300447.51,  18.41,  0.614,  650014.2,   300446.914, 18.473],
         [650001.18, 312862.23,  8.79,   40.338, 650014.526, 312899.965, 13.797],
         [650001.19, 312861.88,  9.15,   40.619, 650014.526, 312899.965, 13.797]]
second = [[300441.668,    1],
          [300443.182,    2],
          [300442.085,    3],
          [300444.395,    4],
          [312902.819,    5],
          [300444.792,    6],
          [312905.096,    7],
          [300447.197,    8],
          [300446.497,    9],
          [300446.914,    10],
          [312899.965,    11]]

second_dict = {i[0]: i[1] for i in second}
first_second = [item + [second_dict[item[5]]] for item in first]
print first_second[0]

---

您只需将第二个数组转换为dict：

second_list = [[300441.668,    1],
[300443.182,    2],
[300442.085,    3],
[300444.395,    4],
[312902.819,    5],
[300444.792,    6],
[312905.096,    7],
[300447.197,    8],
[300446.497,    9],
[300446.914,    10],
[312899.965,    11]]

print(dict(second_list))
# {312899.965: 11, 300447.197: 8, 300443.182: 2, 300444.792: 6, 300441.668: 1, 300444.395: 4, 300446.497: 9, 312905.096: 7, 312902.819: 5, 300442.085: 3, 300446.914: 10}

---

它为您提供了第一个数组的快速查找表。不需要将第一个数组转换为任何其他数组。如果找不到键，您可能希望与默认值一起使用。

您能解释一下为什么从第二个目录中获取项[5]而不仅仅是值吗？我获取的是与

项[5]

匹配的键的值。出于某种原因，我没有向新列表添加值。当我打印第一秒[0]时，我只得到了7条记录，而不是8条。所以我猜并不是将新记录添加到最终输出中。但我的另一方面是，从字典中正确查找键并没有添加到新列表中。它应该是8，在我的机器上它是8。我以前从未将字典与数组进行过比较。您能解释一下如何使用它吗？

second_list = [[300441.668,    1],
[300443.182,    2],
[300442.085,    3],
[300444.395,    4],
[312902.819,    5],
[300444.792,    6],
[312905.096,    7],
[300447.197,    8],
[300446.497,    9],
[300446.914,    10],
[312899.965,    11]]

print(dict(second_list))
# {312899.965: 11, 300447.197: 8, 300443.182: 2, 300444.792: 6, 300441.668: 1, 300444.395: 4, 300446.497: 9, 312905.096: 7, 312902.819: 5, 300442.085: 3, 300446.914: 10}