Arrays ClosedInterval<；字符串>；用Swift[串]

为什么:

let i = 1...100
let s = [Int](i)

屈服

[1, 2, 3, ..., 100]

Cannot invoke initializer for type '[String]' with an argument list of type '(ClosedInterval<String>)'

true

但是

屈服

[1, 2, 3, ..., 100]

Cannot invoke initializer for type '[String]' with an argument list of type '(ClosedInterval<String>)'

true

屈服

[1, 2, 3, ..., 100]

Cannot invoke initializer for type '[String]' with an argument list of type '(ClosedInterval<String>)'

true

---

Int

符合

ForwardIndexType

，因此在

let i = 1...100

let i = "a"..."z"

…

是操作员

public func ...<Pos : ForwardIndexType where Pos : Comparable>(start: Pos, end: Pos) -> Range<Pos>

public func ...<Bound : Comparable>(start: Bound, end: Bound) -> ClosedInterval<Bound>

…

是操作员

public func ...<Pos : ForwardIndexType where Pos : Comparable>(start: Pos, end: Pos) -> Range<Pos>

public func ...<Bound : Comparable>(start: Bound, end: Bound) -> ClosedInterval<Bound>

产生

true

在Swift 3中，范围和间隔类型已重命名并 重组：

"1" ... "100"  // CountableClosedRange<Int>
"a" ... "z"    // ClosedRange<String>

结果是

["a", "b", "c", ... , "z"]

作为

字符的数组

或

字符串的数组