Arrays AS3在循环中创建多个数组
我试图制作六个数组,所以我都是手工创建的。我知道有一种方法可以让这场混战变得更短,但我已经忘记了Arrays AS3在循环中创建多个数组,arrays,actionscript-3,loops,random,for-loop,Arrays,Actionscript 3,Loops,Random,For Loop,我试图制作六个数组,所以我都是手工创建的。我知道有一种方法可以让这场混战变得更短,但我已经忘记了 var variant_1:Array = new Array (rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.ge
var variant_1:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
var variant_2:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
var variant_3:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
var variant_4:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
var variant_5:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
var variant_6:Array = new Array
(rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(), rp.getNum(),
"", "", "", "", "", "", "", "", "", "", "", "");
注意:getNum()是一个函数,它给我一个介于1和90之间的随机数字范围,然后我将它们分配给一个动态创建的表
注2:数组中的空值是表中的空单元格,因为在一个9x3的表中,我需要15个数字和12个空格
注3:是的,这是一个宾果游戏
谢谢。您可以使用for循环
for(var i:int=0; i<10; i++) {
trace(i);
}
for(var i:int=0;i您可以使用for循环
for(var i:int=0; i<10; i++) {
trace(i);
}
for(变量i:int=0;i
//使用您的变体:
//变体[0][0]与您的变体_1[0]相同
function createVariants(numVariants : int, numPrefilled : int, numEmpty : int) : Array{
var variants : Array = [];
for(var i : int = 0;i<numVariants;i++){
var variant : Array = [];
for(var j : int = 0;j<numPrefilled ;j++){
variant.push(rp.getNum());
}
for(var j : int = 0;j<numEmpty ;j++){
variant.push("");
}
variants.push(variant);
}
return variants;
}
函数createVariants(numVariants:int,numPrefilled:int,numEmpty:int):数组{
变量:数组=[];
对于(变量i:int=0;i
//使用您的变体:
//变体[0][0]与您的变体_1[0]相同
function createVariants(numVariants : int, numPrefilled : int, numEmpty : int) : Array{
var variants : Array = [];
for(var i : int = 0;i<numVariants;i++){
var variant : Array = [];
for(var j : int = 0;j<numPrefilled ;j++){
variant.push(rp.getNum());
}
for(var j : int = 0;j<numEmpty ;j++){
variant.push("");
}
variants.push(variant);
}
return variants;
}
函数createVariants(numVariants:int,numPrefilled:int,numEmpty:int):数组{
变量:数组=[];
对于(var i:int=0;i基于Paul的答案,您还可以使用2d数组来存储每个数组,这样做的好处是可以使用循环创建所需的任意多个数组变体(成本是必须维护2d数组所增加的复杂性)
使用二维阵列可能类似于:
function createArrayVarient(){
var result:Array = new Array();
var counter:int;
// 15 as there are 15 numbers added first
for(counter = 0; counter < 15; counter++){
result.push(rp.getNum());
}
// 12 for the number of "" added
for(counter = 0; counter < 12; counter++){
result.push("");
}
return result;
}
var arrayVarients:Array = new Array();
// 6 as you have 6 array variants in your sample
for(var counter = 0; counter < 6; counter++){
arrayVarients.push(createArrayVarient());
}
要访问数组变量中的每个值,它将转到(使用2个索引):
根据Paul的答案,您还可以使用2d数组来存储每个数组,这样做的好处是可以使用循环创建所需的任意多个数组变体(成本是维护2d数组所增加的复杂性)
使用二维阵列可能类似于:
function createArrayVarient(){
var result:Array = new Array();
var counter:int;
// 15 as there are 15 numbers added first
for(counter = 0; counter < 15; counter++){
result.push(rp.getNum());
}
// 12 for the number of "" added
for(counter = 0; counter < 12; counter++){
result.push("");
}
return result;
}
var arrayVarients:Array = new Array();
// 6 as you have 6 array variants in your sample
for(var counter = 0; counter < 6; counter++){
arrayVarients.push(createArrayVarient());
}
要访问数组变量中的每个值,它将转到(使用2个索引):
我想这就是你想要的
var iVariantCount:int = 6;//number of variants
var arrVariants:Array = new Array();//this will hold your variants array (variant_1,variant_2,etc)
var iVariantLength:int = 27;//total no fo elements in a variant array
var iRandomNumCount:int = 15;//no of random numbers in a variant array
for (var i:int = 0; i<iVariantCount ; i++)
{
var arrVariant:Array = new Array();
for (var j:int = 0; j < iVariantCount ; j++)
{
if (i < iRandomNumCount)
{
arrVariant.push(rp.getNum());
}
else
{
arrVariant.push("");
}
arrVariants.push(arrVariant);
}
}
//Check the result
for (i = 0; i<arrVariants.length ; i++)
{
trace("Variant_" + i + ": " + arrVariants[i]);
}
var iVariantCount:int=6;//变量数
var arrVariants:Array=new Array();//这将保存变量数组(变量1、变量2等)
var iVariantLength:int=27;//变量数组中总共没有fo元素
var iRandomNumCount:int=15;//变量数组中的随机数
对于(var i:int=0;i我想这就是你想要的
var iVariantCount:int = 6;//number of variants
var arrVariants:Array = new Array();//this will hold your variants array (variant_1,variant_2,etc)
var iVariantLength:int = 27;//total no fo elements in a variant array
var iRandomNumCount:int = 15;//no of random numbers in a variant array
for (var i:int = 0; i<iVariantCount ; i++)
{
var arrVariant:Array = new Array();
for (var j:int = 0; j < iVariantCount ; j++)
{
if (i < iRandomNumCount)
{
arrVariant.push(rp.getNum());
}
else
{
arrVariant.push("");
}
arrVariants.push(arrVariant);
}
}
//Check the result
for (i = 0; i<arrVariants.length ; i++)
{
trace("Variant_" + i + ": " + arrVariants[i]);
}
var iVariantCount:int=6;//变量数
var arrVariants:Array=new Array();//这将保存变量数组(变量1、变量2等)
var iVariantLength:int=27;//变量数组中总共没有fo元素
var iRandomNumCount:int=15;//变量数组中的随机数
对于(var i:int=0;这是一个非常好的循环介绍。而且,你的解决方案非常好。这是一个非常好的循环介绍。而且,你的解决方案非常好。它冻结了Flash IDE。可能是一个无限循环。很抱歉,第二个循环中出现了错误,我编写了i++而不是j++。我已经编辑了我的答案。现在试试。它冻结了Flash IDE。可能是一个错误。)有限循环。很抱歉,第二个循环出错,我编写了i++而不是j++。我已编辑了我的答案。请立即尝试。