Arrays swift中基于匹配值的字典和过滤器迭代数组

我的数据如下所示：

[["-MXpvzmZdbqzrjND8w9F": {
    lid = "-MW6eEidZFCLeeZ0uBk1";
    message = hi;
    timeStamp = 1617960107264;
    title = "Sambhar Dosa";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}, "-MXq5NAyrkk4ZcvRFM7T": {
    lid = "-MW6eEidZFCLeeZ0uBk1";
    message = "how ru?";
    timeStamp = 1617962828647;
    title = "Sambhar Dosa";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}], ["-MXqa5-pkC28lY_Q_hpZ": {
    lid = "-MWwEpHAhIdhN0i5sltB";
    message = "hi nice cycle";
    timeStamp = 1617971142820;
    title = "Cycle for kids";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}]]

struct SomeData1
{
let dict: [String: Any]

var lid: String? { dict["lid"] as? String }
var message: String? { dict["message"] as? String }
var timeStamp: Double { dict["timeStamp"] as? Double ?? 0.0 }
var title: String? { dict["title"] as? String }
var user: String? { dict["user"] as? String }
var owner: String? { dict["owner"] as? String }
   
}

现在，该值由变量testarray定义。仅为方便而给出的名称。 testarray是var testarray=[String:[String:Any]]

内部字典使用结构定义，如下所示：

[["-MXpvzmZdbqzrjND8w9F": {
    lid = "-MW6eEidZFCLeeZ0uBk1";
    message = hi;
    timeStamp = 1617960107264;
    title = "Sambhar Dosa";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}, "-MXq5NAyrkk4ZcvRFM7T": {
    lid = "-MW6eEidZFCLeeZ0uBk1";
    message = "how ru?";
    timeStamp = 1617962828647;
    title = "Sambhar Dosa";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}], ["-MXqa5-pkC28lY_Q_hpZ": {
    lid = "-MWwEpHAhIdhN0i5sltB";
    message = "hi nice cycle";
    timeStamp = 1617971142820;
    title = "Cycle for kids";
    user = 1QSU0c1q8QNrZzmICXGClC0o86E3;
}]]

struct SomeData1
{
let dict: [String: Any]

var lid: String? { dict["lid"] as? String }
var message: String? { dict["message"] as? String }
var timeStamp: Double { dict["timeStamp"] as? Double ?? 0.0 }
var title: String? { dict["title"] as? String }
var user: String? { dict["user"] as? String }
var owner: String? { dict["owner"] as? String }
   
}

因此testarray也可以读作var testarray=[String:[SomeData1]]

现在，根据上述数据，当lid与特定值匹配时，只有这些数据存储在名为dataToDisplay的变量中，该变量定义为var dataToDisplay=SomeData1

我已经用下面的代码过滤了上面的数据

     var sortStep1 = self.testArray.map {
                dict in dict.map {
                ($0.key, SomeData1(dict: $0.value))
                }.filter {$0.1.lid == self.listid}
    }

print("sortStep1 is",sortStep1)

为sortStep1显示的值为

[[（“-MY5aPJ--Xoot_wlGSqS”，Hunger.ChatVC.SomeData1（dict:[“所有者”：bPqDIJvYX7g7ZhE8ap0TgeYMYjE2，“盖子”：-mw6eedzfcleez0ubk1，“用户”：1QSU0c1q8QNrZzmICXGClC0o86E3，“时间戳”：161823966661393，“消息”：hi，“标题”：Sambhar Dosa]），（-MY5b-WT4AoWWa7c1eQT），“Hunger.ChatVC.some1（dict:“标题”：sambdosha-Sambhar，“用户”：sambdosa，“数据产品”，nice”：1QSU0c1q8QNrZzmICXGClC0o86E3，“时间戳”：1618239817904，“盖子”：-MW6eEidZFCLeeZ0uBk1，“所有者”：BPQDIJVYX7G7ZHE8AP0TGEYMJE2]），[]

这里还显示了一个空数组。我不想要这个空数组。我只想显示匹配列表。

---

获取匹配lid的代码是否正确？

尝试添加第二个过滤器，检查数组是否为空，类似于将

filter{！$0.values.isEmpty}

添加到同一个函数？添加到您发布的代码yesvar sortStep1=self.testArray.map{dict in dict.map{（$0.key，SomeData1（dict:$0.value））}.filter{$0.1.lid==self.listid}.filter{！$0.values.isEmpty}将

.filter（{！$0.isEmpty}）

添加到

sortStep1

，它应该可以完成这个任务。