Asp.net mvc 5 ASP.NET MVC5路由-文章名称Url

我希望我的应用程序的行为如下所示：

Url= ->控制器=物品 ->行动=索引

控制器中的索引方法如下所示：

    public ActionResult Index(string title)
    {
        var article = GetArticle(title);
        return View(article);
    }

我以这种方式配置了我的路由：

    public static void RegisterRoutes(RouteCollection routes)
    {
        routes.IgnoreRoute("{resource}.axd/{*pathInfo}");

        routes.MapRoute(
          name: "Article",
          url: "{title}",
          defaults: new { controller = "Article", action = "Index" }
        );

        routes.MapRoute(
            name: "Default",
            url: "{controller}/{action}/{id}",
            defaults: new { controller = "Home", action = "Index", id = UrlParameter.Optional }
        );
    }

问题是当我需要导航到ContactController的索引方法时：

它试图找到title==contact的文章

---

我知道我可以使用像mydomain/articles/{title}这样的路由，但我真的希望避免这种情况。

我对路由约束不太了解，但我设法解决了这个问题

我将把我的博客标题改为contains-。我的超级文章

这是我的路线配置：

        routes.MapRoute(
          name: "Article",
          url: "{title}",
          defaults: new { controller = "Article", action = "Index" },
          constraints: new { title = @"^.*-.*$" } 
        );

---

您可以编写自定义约束：

public class MyConstraint : IRouteConstraint
{
    // suppose this is your blogPost list. In the real world a DB provider 
    private string[] _myblogsTitles = new[] { "Blog1", "Blog2", "Blog3" };

    public bool Match(HttpContextBase httpContext, Route route, string parameterName, RouteValueDictionary values, RouteDirection routeDirection)
    {
        // return true if you found a match on your blogs list otherwise false
        // in the real world you could query from DB to match blogs instead of searching from the array.  
        if(values.ContainsKey(parameterName))
        {
             return _myblogsTitles.Any(c => c == values[parameterName].ToString());
        }
        return false;
    }
}

然后将此约束添加到路线中

routes.MapRoute(
    name: "Article",
    url: "{title}",
    defaults: new { controller = "Article", action = "Index" }
    constraints: new { title= new MyConstraint() }
);

看见