Asp.net Ajax Modelpop不工作

Asp.net Ajax Modelpop不工作,asp.net,ajax,Asp.net,Ajax,我在gridview中使用了ajax modelpop: <asp:GridView ID="grdInbox" runat="server" CellPadding="0" AutoGenerateColumns="False" Width="100%"> <Columns> <asp:TemplateField> <ItemTemplate> <

我在gridview中使用了ajax modelpop:

<asp:GridView ID="grdInbox" runat="server" CellPadding="0"
       AutoGenerateColumns="False" Width="100%">
    <Columns>
        <asp:TemplateField>
            <ItemTemplate>
                <asp:Button CssClass="blueButton" ID="btnReply" Text="Reply" style="background-color:#FFA600;" runat="server"/>
                    <cc1:ModalPopupExtender
                        ID="modlpopupReply" runat="server" TargetControlID="btnReply" PopupControlID="pnlReply" CancelControlID="btnCancelReply" DropShadow="true" Enabled="True" X="100" Y="100">
                    </cc1:ModalPopupExtender>
            </ItemTemplate>
        </asp:TemplateField>
    </Columns>
</asp:GridView>    

<asp:Panel ClientIDMode="Static" ID="pnlReply" runat="server">
    <div>
        <div style="font-size:20px;">Reply Message</div>
        <asp:Button ID="btnSend" runat="server" Text="Send" ClientIDMode="Static"    CssClass="blueButton" />
        <asp:Button ID="btnCancelReply" runat="server" ClientIDMode="Static" Text="Cancel" CssClass="blueButton" style="background-color:#FFA600;"/>
    </div>
</asp:Panel>

回复信息
问题是:

  • 它不会出现在屏幕上
  • 如何在弹出窗口中传递gridview其他列的值

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