Assembly 如何将值从输入AL移动到寻址寄存器,如16位的BX
我陷入了这段代码中…我想从用户那里获取一个输入,并将其移动到寄存器中…但寄存器是16位的,输入存储在8位的Al中。。。有没有办法将值从AL移到BX这样的寄存器…我这样做是因为我想在数组中使用BX,比如数组[BX]。。。。请帮我解决这个问题Assembly 如何将值从输入AL移动到寻址寄存器,如16位的BX,assembly,Assembly,我陷入了这段代码中…我想从用户那里获取一个输入,并将其移动到寄存器中…但寄存器是16位的,输入存储在8位的Al中。。。有没有办法将值从AL移到BX这样的寄存器…我这样做是因为我想在数组中使用BX,比如数组[BX]。。。。请帮我解决这个问题 .MODEL SMALL .STACK 100H .DATA MSG DB 10,13,"TIC TAC TOE $" MSG1 DB " $" ARR1 DB '1','2','3','4','5','6','7','8','9' MSG2 DB 10,
.MODEL SMALL
.STACK 100H
.DATA
MSG DB 10,13,"TIC TAC TOE $"
MSG1 DB " $"
ARR1 DB '1','2','3','4','5','6','7','8','9'
MSG2 DB 10,13,"PLAYER 1 WIN $"
MSG3 DB 10,13,"PLAYER 2 WIN $"
MSG4 DB 10,13,"GAME DRAW $"
VAR DW ?
PLAYER1 EQU 'X'
PLAYER2 EQU 'O'
.CODE
MAIN PROC
MOV AX , @DATA
MOV DS , AX
NEXT_LINE1:
MOV BX , 0 ;counter
NEXT_LINE: ;this loop will shape the array in matrix form
MOV AH , 2
MOV DL , 0AH ; move on next line
INT 21H
MOV DL , 0DH
INT 21H
MOV CX , 3
L1:
MOV AH , 2 ;display content of array
MOV DL , ARR1[BX]
INT 21H
MOV AH , 9
LEA DX , MSG1 ;msg to show space between characters.. like 1 2 3 ,,,, 4 5 6
INT 21H
INC BX
CMP BX , 10
JE ELSE_IF
LOOP L1
JMP NEXT_LINE
ELSE_IF:
MOV BX , 0
;take input from user
MOV AH , 1
INT 21H
SUB AL , 1
ADD BX , AL ;try to save it into register like bx , si , di ...
MOV DX , 'X'
MOV ARR1[BX] , DL
JMP NEXT_LINE1
MOV AH , 4CH
INT 21H
MAIN ENDP
END MAIN
有几个选择:
movzx bx, al ; move with zero-extend
movsx bx, al ; move with sign extend
xor bx, bx ; clear bx
mov bl, al
有几个选择:
movzx bx, al ; move with zero-extend
movsx bx, al ; move with sign extend
xor bx, bx ; clear bx
mov bl, al
正如@michael所说,有一些方法。(8086总成): 更正确的方法:
cbw ; sign extend al into ax (if it is negative)
mov bx, ax
正如@michael所说,有一些方法。(8086总成): 更正确的方法:
cbw ; sign extend al into ax (if it is negative)
mov bx, ax
可能重复,请在此处检查答案:可能重复,请在此处检查答案: