Assembly 尝试在汇编语言中翻转三角形

我的代码的输出是

INCLUDE Irvine32.inc
.code
main PROC

        mov ecx, 6 
L1:
        call Proc1
        call CRLF
        loop L1

        exit
main ENDP

proc1 PROC  USES ecx
        mov  al, 'A'
L2:     call WriteChar
        inc al
        loop L2
        ret
proc1 ENDP

END main

以三角形的形式向下，但我需要将它翻转到它所在的位置

ABCDEF
ABCDE
ABCD
ABC
AB
A

编辑：

尝试镜像直角三角形

A
AB
ABC
ABCD
ABCDE
ABCDEF

---

正如@Jester所建议的，计数是解决方案，但我只在一个循环中对您的代码做了一点更改：

A            A
AB          BA
ABC        CBA
ABCD      DCBA
ABCDE    EDCBA
ABCDEF  FEDCBA

现在镜子：想法是在字母前打印空白：

A
AB
ABC
ABCD
ABCDE
ABCDEF

两个三角形：只需在空格前后调用Proc1即可显示两个三角形，非常重要的是，空格计数器EBP必须为12，以便进行适当的分隔，并且在proc空格中，EBP必须减少2：

INCLUDE Irvine32.inc
.code
main PROC

        mov ecx, 1     ;<=============================
        mov ebp, 6     ;EBP IS USED AS REVERSE COUNTER FOR BLANK SPACES.

L1:     call spaces    ;</////////////////////////////
        call Proc1
        call CRLF
;       loop L1        ;<============================= NO MORE LOOP HERE.
        inc  ecx       ;<============================= CX++.
        cmp  ecx, 6    ;<============================= 
        jbe  L1        ;<============================= IF (CX <= 6) REPEAT.

        exit
main ENDP

proc1 PROC  USES ecx
        mov  al, 'A'
L2:     call WriteChar
        inc al
        loop L2
        ret
proc1 ENDP

spaces PROC              ;</////////////////////////////
        push ebp         ;PRESERVE CURRENT SPACES COUNTER.
        mov  al, ' '     ;SPACE TO PRINT.
L3:     call WriteChar   ;PRINT SPACE.
        dec  ebp         ;DECREASE COUNTER.
        jnz  L3          ;IF COUNTER > 0 REPEAT.
        pop  ebp         ;RESTORE SPACES COUNTER.
        dec  ebp         ;DECREASE ONE SPACE FOR THE NEXT LINE.
        ret              ;</////////////////////////////
spaces ENDP              ;</////////////////////////////

END main

替代解决方案：

INCLUDE Irvine32.inc
.code
main PROC

        mov ecx, 1     ;<=============================
        mov ebp, 12     ;EBP IS USED AS REVERSE COUNTER FOR BLANK SPACES.

L1:     call Proc1     ;LEFT TRIANGLE ! ! !
        call spaces    ;</////////////////////////////
        call Proc1     ;RIGHT TRIANGLE ! ! !
        call CRLF
;       loop L1        ;<============================= NO MORE LOOP HERE.
        inc  ecx       ;<============================= CX++.
        cmp  ecx, 6    ;<============================= 
        jbe  L1        ;<============================= IF (CX <= 6) REPEAT.

        exit
main ENDP

proc1 PROC  USES ecx
        mov  al, 'A'
L2:     call WriteChar
        inc al
        loop L2
        ret
proc1 ENDP

spaces PROC              ;</////////////////////////////
        push ebp         ;PRESERVE CURRENT SPACES COUNTER.
        mov  al, ' '     ;SPACE TO PRINT.
L3:     call WriteChar   ;PRINT SPACE.
        dec  ebp         ;DECREASE COUNTER.
        jnz  L3          ;IF COUNTER > 0 REPEAT.
        pop  ebp         ;RESTORE SPACES COUNTER.
        sub  ebp, 2      ;DECREASE 2 SPACES FOR THE NEXT LINE.
        ret              ;</////////////////////////////
spaces ENDP              ;</////////////////////////////

END main

---

让我们看看，如果ecx=6，您要打印1个字符，如果ecx=2，您要打印2个字符，如果ecx=1，您要打印6个字符。要是有一个简单的数学运算就好了。或者，您可以向上计数而不是向下计数：您有两个嵌套循环，使用ecx作为计数器寄存器，而不使用堆栈。你是如何得到这个输出的？@owacoder使用ecx做的魔法：@Jester-ah。我已经习惯了NASM和GAS，那里的一切都是公开的-你的实际问题是什么？其他一切似乎都准备好了。非常感谢，现在我正试着倒转直角三角形，你知道怎么做吗？@Mr.Robot，mirror？你是说uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu！镜像三角形我编辑了我的答案，看看。你知道如何镜像三角形吗？当然知道。但是你也可以，只要你花5分钟在上面。这并不十分复杂，你只需要按正确的顺序打印一些空格和字母。

INCLUDE Irvine32.inc
.code
main PROC

        mov ecx, 1     ;<=============================
        mov ebp, 12     ;EBP IS USED AS REVERSE COUNTER FOR BLANK SPACES.

L1:     call Proc1     ;LEFT TRIANGLE ! ! !
        call spaces    ;</////////////////////////////
        call Proc1     ;RIGHT TRIANGLE ! ! !
        call CRLF
;       loop L1        ;<============================= NO MORE LOOP HERE.
        inc  ecx       ;<============================= CX++.
        cmp  ecx, 6    ;<============================= 
        jbe  L1        ;<============================= IF (CX <= 6) REPEAT.

        exit
main ENDP

proc1 PROC  USES ecx
        mov  al, 'A'
L2:     call WriteChar
        inc al
        loop L2
        ret
proc1 ENDP

spaces PROC              ;</////////////////////////////
        push ebp         ;PRESERVE CURRENT SPACES COUNTER.
        mov  al, ' '     ;SPACE TO PRINT.
L3:     call WriteChar   ;PRINT SPACE.
        dec  ebp         ;DECREASE COUNTER.
        jnz  L3          ;IF COUNTER > 0 REPEAT.
        pop  ebp         ;RESTORE SPACES COUNTER.
        sub  ebp, 2      ;DECREASE 2 SPACES FOR THE NEXT LINE.
        ret              ;</////////////////////////////
spaces ENDP              ;</////////////////////////////

END main

proc1 PROC  USES ecx
        neg ecx
        add ecx, 7   ; print 7-ecx letters
        mov  al, 'A'
L2:     call WriteChar
        inc al
        loop L2
        ret
proc1 ENDP