Asterisk 星号：进入队列时向呼叫者播放消息

我很难做到这一点：当进入队列时，我想向呼叫者播放欢迎信息

调用者首先进入一个短队列（

initQ

），但不宣布，然后进入

mynewQ

，我想在那里播放自定义欢迎消息

到目前为止，我只能播放默认的

队列youarenext.alaw

：

文件

queues.conf

：

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113
announce-to-first-user = yes
periodic-announce = custom/bienvenue

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
musicclass=mynewQmoh
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113

[mynewQmoh]
mode=files
announcement=custom/bienvenue
directory=moh

计划如下：

...
exten = takeCall,1,Queue(initQ,Crn)
 same = n,Queue(mynewQ,Cn)

...
[mynewQ-context]

exten = 1,1,NoOp("mynewQ-context : key 1 pressed to leave a message")
 same = n,VoiceMail(999@boitevocale,start)
 same = n,Playback(goodbye)
 same = n,Hangup()

我的目标是播放我自己的欢迎信息

custom/bienvenue

我试过使用

queue thankyou

，

periodic annound

在

queues.conf.sample

文件中找到的其他文件，但没有很好的结果

因为我定义了一个上下文，所以我也探讨了这一点，但在进入这个上下文时我无法播放消息。上下文用于捕获DTMF，然后触发操作：留下消息，请求回拨。。。这样做很好。

你可以这样做

exten = enterQ,1,Answer
same => n,Playback(intro-message)
same => n,Queue(initQ,Crn)

---

或者将您的消息添加到musiconhold中，并确保您的hold音乐始终从开始开始播放（请参阅musiconhold.conf选项）。

以下是我最终完成此操作的方法。非常感谢

arheops

，感谢他建议更改hold音乐

文件

queues.conf

：

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113
announce-to-first-user = yes
periodic-announce = custom/bienvenue

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
musicclass=mynewQmoh
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113

[mynewQmoh]
mode=files
announcement=custom/bienvenue
directory=moh

文件

musiconhold.conf

：

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113
announce-to-first-user = yes
periodic-announce = custom/bienvenue

[general]

[initQ]
strategy=ringall                
timeout=15
member => PJSIP/111
member => PJSIP/112
member => PJSIP/112

[mynewQ]
strategy=ringall
timeout=120
context=mynewQ-context
musicclass=mynewQmoh
ringinuse=no
member => PJSIP/111
member => PJSIP/112
member => PJSIP/113

[mynewQmoh]
mode=files
announcement=custom/bienvenue
directory=moh

---

而拨号计划保持不变。

您的拨号计划在哪里？我添加了更多的细节谢谢，但不确定是否收到：如果在进入队列之前播放了介绍消息，则呼叫者必须等到消息结束（进入队列）后才能按DTMF键。知道该消息的呼叫者将希望在广播结束前按键！我想在进入队列时播放消息。是的，他必须等待。更重要的是，当在队列中播放IVR消息时，他也会等待，当播放IVR或时间公告时，队列不会响。此外，你不能到处按数字，只有在播放公告时才可以。你可以使用chan_spy或通过更改hold音乐在后台播放。通过使用features.conf feature，您可以接受1 everywhere。应用程序队列根本不支持这一点。