Automation 总是得到；无法转换步骤“的参数”；尝试将自定义对象参数传递给步骤定义时出错？

我的功能文件如下所示：

Given User is on Home Page
    When User Navigate to LogIn Page
    And User enters Credentials to LogIn
    | Username   | Password |
    | testuser_1 | Test@153 |
    | testuser_2 | Test@154 |
    Then Message displayed Login Successfully

步骤定义为：

public void user_enters_testuser_and_Test(List<Credentials>  usercredentials) throws Throwable {

        //Write the code to handle Data Table
        for (Credentials credentials : usercredentials) {           
            driver.findElement(By.id("log")).sendKeys(credentials.getUsername()); 
            driver.findElement(By.id("pwd")).sendKeys(credentials.getPassword());
            driver.findElement(By.id("login")).click();
            }       
    }

当我运行代码时，总是出现以下错误：

cucumber.runtime.CucumberException: Could not convert arguments for step [^User enters Credentials to LogIn$] defined at 'stepDefinitions.ConsumerServiceEnquiry.ConsumerSteps.user_enters_testuser_and_Test(Credentials>) in file:/C:/Users/jxz36/eclipse-workspace/SDBCucumberTestng/bin/'.

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我到处都找过，看到很多类似的例子。所以我认为这一定是一些基本的错误或缺少配置。谁能帮我解决这个问题？非常感谢

我想你在cucumber 3及以上。如有，请参阅本条—

将现有的转换器更换为此

registry.defineDataTableType(new DataTableType(Credentials.class, new TableEntryTransformer<Credentials>() {
            @Override
            public Credentials transform(Map<String, String> entry) {
                return new Credentials(entry.get("Username"),entry.get("Password"));
            }
        }));

---

}

什么是黄瓜版？非常感谢蚱蜢。是的，我昨天就知道了，这是黄瓜版的问题。我已经降级到2.3.0版。问题已经解决了！谢谢这不是版本问题，只是处理自动转换的方式已经升级。由于xstream与java9不兼容而被删除，这是处理转换的新方法。

registry.defineDataTableType(new DataTableType(Credentials.class, new TableEntryTransformer<Credentials>() {
            @Override
            public Credentials transform(Map<String, String> entry) {
                return new Credentials(entry.get("Username"),entry.get("Password"));
            }
        }));

 public Credentials() {
    }
    public Credentials(String username, String password) {
        this.username = username;
        this.password = password;