Automation 伊莎贝尔的自动求解器没有找到正确的定理

陈述之后

theorem "2=2"

伊莎贝尔建议如下：

proof (prove)
goal (1 subgoal):
 1. 2 = 2 
Auto solve_direct: the current goal can be solved directly with
  BNF_Composition.DEADID.map_ident: ?t = ?t
  BNF_Composition.DEADID.rel_refl: ?x = ?x
  BNF_Composition.DEADID.rel_refl_strong: ?x = ?x
  Basic_BNF_LFPs.xtor_rel: ?R (Basic_BNF_LFPs.xtor ?x) (Basic_BNF_LFPs.xtor ?y) = ?R ?x ?y
  Basic_BNF_LFPs.xtor_set: ?f (Basic_BNF_LFPs.xtor ?x) = ?f ?x

但它没有找到明显的HOL.refl，因为它更优雅

为什么会这样？为什么解算器只使用这些神秘的长标识符？

直接求解方法的默认限制为5个解。您可以通过以下方式进行更改：

 declare [[solve_direct_max_solutions=1000]] 

然后您将获得以下输出：

Auto solve_direct: the current goal can be solved directly with
BNF_Composition.DEADID.map_ident: ?t = ?t
BNF_Composition.DEADID.rel_refl: ?x = ?x
BNF_Composition.DEADID.rel_refl_strong: ?x = ?x
Basic_BNF_LFPs.xtor_rel: ?R (Basic_BNF_LFPs.xtor ?x) (Basic_BNF_LFPs.xtor ?y) = ?R ?x ?y
Basic_BNF_LFPs.xtor_set: ?f (Basic_BNF_LFPs.xtor ?x) = ?f ?x
Complete_Lattices.Inf.INF_id_eq: ?Inf (id ` ?A) = ?Inf ?A
Complete_Lattices.Inf.INF_identity_eq: ?Inf ((λx. x) ` ?A) = ?Inf ?A
Complete_Lattices.Inf.INF_image: ?Inf (?g ` ?f ` ?A) = ?Inf ((?g ∘ ?f) ` ?A)
Complete_Lattices.Sup.SUP_id_eq: ?Sup (id ` ?A) = ?Sup ?A
Complete_Lattices.Sup.SUP_identity_eq: ?Sup ((λx. x) ` ?A) = ?Sup ?A
Complete_Lattices.Sup.SUP_image: ?Sup (?g ` ?f ` ?A) = ?Sup ((?g ∘ ?f) ` ?A)
HOL.refl: ?t = ?t
SMT.z3_rule(160): ?t = ?t

solve_direct方法的默认限制为5个解决方案。您可以通过以下方式进行更改：

 declare [[solve_direct_max_solutions=1000]] 

然后您将获得以下输出：

Auto solve_direct: the current goal can be solved directly with
BNF_Composition.DEADID.map_ident: ?t = ?t
BNF_Composition.DEADID.rel_refl: ?x = ?x
BNF_Composition.DEADID.rel_refl_strong: ?x = ?x
Basic_BNF_LFPs.xtor_rel: ?R (Basic_BNF_LFPs.xtor ?x) (Basic_BNF_LFPs.xtor ?y) = ?R ?x ?y
Basic_BNF_LFPs.xtor_set: ?f (Basic_BNF_LFPs.xtor ?x) = ?f ?x
Complete_Lattices.Inf.INF_id_eq: ?Inf (id ` ?A) = ?Inf ?A
Complete_Lattices.Inf.INF_identity_eq: ?Inf ((λx. x) ` ?A) = ?Inf ?A
Complete_Lattices.Inf.INF_image: ?Inf (?g ` ?f ` ?A) = ?Inf ((?g ∘ ?f) ` ?A)
Complete_Lattices.Sup.SUP_id_eq: ?Sup (id ` ?A) = ?Sup ?A
Complete_Lattices.Sup.SUP_identity_eq: ?Sup ((λx. x) ` ?A) = ?Sup ?A
Complete_Lattices.Sup.SUP_image: ?Sup (?g ` ?f ` ?A) = ?Sup ((?g ∘ ?f) ` ?A)
HOL.refl: ?t = ?t
SMT.z3_rule(160): ?t = ?t