Azure 将带有特殊参数的变量传递到ARM模板时出错

我有一个主模板和两个链接模板。我想用特殊字符传递参数，但有一个错误。有人知道怎么修吗？ 该问题是由上一个链接模板定义中的“servicebus_1_connectionString”参数引起的。我提供了错误信息，并修改了《秘密》中的几个字母，这样您就有了一个概览，但仍然没有透露我的秘密

{
  "$schema": "https://schema.management.azure.com/schemas/2019-04-01/deploymentTemplate.json#",
  "contentVersion": "1.0.0.0",
    "parameters": {
        "containerUri": {
            "type": "string"
        },
        "containerSasToken": {
            "type": "string"
        }
    },
  "variables": {},
    "resources": [
        {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "AzureServiceBusLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'Infrastructure/AzureServiceBus.json', parameters('containerSasToken'))]"
                }
            }
        },
        {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "AppFunctionsLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'Infrastructure/AppFunctions.json', parameters('containerSasToken'))]"
                }
            }
        },
        {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "LogicAppLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'LogicApp.json', parameters('containerSasToken'))]"
                },
                 "parameters": {
                "servicebus_1_connectionString": "[reference('AzureServiceBusLinkedTemplate').outputs.SBNamespaceDefaultConnectionString.value]"
            }
            },
            "dependsOn": [
                "AzureServiceBusLinkedTemplate"
            ]
        }
    ],
  "outputs": {
  }
}

编辑： 我通过将传递参数的方式更改为以下方式解决了此问题：

       {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "LogicAppLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'LogicApp.json', parameters('containerSasToken'))]"
                },
                "parameters": {
                    "servicebus_1_connectionString": {
                        "value": "[reference('AzureServiceBusLinkedTemplate').outputs.SBNamespaceDefaultConnectionString.value]"
                    },
                    "logicAppName": {
                        "value": "DeployedFromVS"
                    }
                }
            },
            "dependsOn": [
                "AzureServiceBusLinkedTemplate"
            ]
        }

   {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "LogicAppLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'LogicApp.json', parameters('containerSasToken'))]"
                },
                "parameters": {
                    "servicebus_1_connectionString": {
                        "value": "[reference('AzureServiceBusLinkedTemplate').outputs.SBNamespaceDefaultConnectionString.value]"
                    },
                    "logicAppName": {
                        "value": "DeployedFromVS"
                    }
                }
            },
            "dependsOn": [
                "AzureServiceBusLinkedTemplate"
            ]
        }

有几种选择：

这更有意义，不要传递它，只使用嵌套模板中的值

好处：不是检索部署输出的值，而是检索嵌套模板中连接字符串的值。更有意义，更安全

base64在嵌套模板中对其进行编码和解码。有一个base64encode\decode函数用于此功能

---

我通过将传递参数的方式更改为以下方式解决了此问题：

       {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "LogicAppLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'LogicApp.json', parameters('containerSasToken'))]"
                },
                "parameters": {
                    "servicebus_1_connectionString": {
                        "value": "[reference('AzureServiceBusLinkedTemplate').outputs.SBNamespaceDefaultConnectionString.value]"
                    },
                    "logicAppName": {
                        "value": "DeployedFromVS"
                    }
                }
            },
            "dependsOn": [
                "AzureServiceBusLinkedTemplate"
            ]
        }

   {
            "type": "Microsoft.Resources/deployments",
            "apiVersion": "2017-05-10",
            "name": "LogicAppLinkedTemplate",
            "properties": {
                "mode": "Incremental",
                "templateLink": {
                    "uri": "[concat(parameters('containerUri'), 'LogicApp.json', parameters('containerSasToken'))]"
                },
                "parameters": {
                    "servicebus_1_connectionString": {
                        "value": "[reference('AzureServiceBusLinkedTemplate').outputs.SBNamespaceDefaultConnectionString.value]"
                    },
                    "logicAppName": {
                        "value": "DeployedFromVS"
                    }
                }
            },
            "dependsOn": [
                "AzureServiceBusLinkedTemplate"
            ]
        }

---

谢谢你的回答。我不想使用嵌套模板，因为我想分离文件以获得更清晰的结构。然而，第3点听起来很合理。你可以称之为链接，这没关系。第3点是所有这些点中最不合理的一点。所列和链接的是不同类型的模板->它实际上不是传递参数的方式，这是唯一的方法